使用Java访问URL
我正在编写一个Android程序,需要访问一个带有GET变量的URL,该变量将被登录到数据库中。我所需要做的就是打开一个URL,这样web服务器将记录数据!我该怎么做 谢谢你用这个使用Java访问URL,java,android,url,Java,Android,Url,我正在编写一个Android程序,需要访问一个带有GET变量的URL,该变量将被登录到数据库中。我所需要做的就是打开一个URL,这样web服务器将记录数据!我该怎么做 谢谢你用这个 Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("URL HERE")); startActivity(browserIntent); 希望这有帮助 编辑: 好的,用这个。它在不打开浏览器的情况下调用URL HttpClient htt
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("URL HERE"));
startActivity(browserIntent);
希望这有帮助
编辑:
好的,用这个。它在不打开浏览器的情况下调用URL
HttpClient httpClient = new DefaultHttpClient();
HttpContext localContext = new BasicHttpContext();
HttpGet httpGet = new HttpGet("URL HERE");
HttpResponse response = httpClient.execute(httpGet, localContext);
您还可以使用HttpUrlConnection。样本代码-
// Given a URL, establishes an HttpUrlConnection and retrieves
// the web page content as a InputStream, which it returns as
// a string.
private String downloadUrl(String myurl) throws IOException {
InputStream is = null;
// Only display the first 500 characters of the retrieved
// web page content.
int len = 500;
try {
URL url = new URL(myurl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(10000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestMethod("GET");
conn.setDoInput(true);
// Starts the query
conn.connect();
int response = conn.getResponseCode();
Log.d(DEBUG_TAG, "The response is: " + response);
is = conn.getInputStream();
// Convert the InputStream into a string
String contentAsString = readIt(is, len);
return contentAsString;
// Makes sure that the InputStream is closed after the app is
// finished using it.
} finally {
if (is != null) {
is.close();
}
}
}
// Reads an InputStream and converts it to a String.
public String readIt(InputStream stream, int len) throws IOException, UnsupportedEncodingException {
Reader reader = null;
reader = new InputStreamReader(stream, "UTF-8");
char[] buffer = new char[len];
reader.read(buffer);
return new String(buffer);
}
显然,由于它是一个netowork调用,所以不能在main/UI线程中执行。因此,您可以在异步任务中完成它 你只想隐藏浏览器吗?不,我不想隐藏它,我只需要访问URL。我不需要查看网页,因为服务器不返回任何数据。这是一个优秀的第三方Android异步Http客户端。如果您根本不需要AsyncTask,只需使用Apache的HttpClient即可
// Given a URL, establishes an HttpUrlConnection and retrieves
// the web page content as a InputStream, which it returns as
// a string.
private String downloadUrl(String myurl) throws IOException {
InputStream is = null;
// Only display the first 500 characters of the retrieved
// web page content.
int len = 500;
try {
URL url = new URL(myurl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(10000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestMethod("GET");
conn.setDoInput(true);
// Starts the query
conn.connect();
int response = conn.getResponseCode();
Log.d(DEBUG_TAG, "The response is: " + response);
is = conn.getInputStream();
// Convert the InputStream into a string
String contentAsString = readIt(is, len);
return contentAsString;
// Makes sure that the InputStream is closed after the app is
// finished using it.
} finally {
if (is != null) {
is.close();
}
}
}
// Reads an InputStream and converts it to a String.
public String readIt(InputStream stream, int len) throws IOException, UnsupportedEncodingException {
Reader reader = null;
reader = new InputStreamReader(stream, "UTF-8");
char[] buffer = new char[len];
reader.read(buffer);
return new String(buffer);
}