Java 如何创建圣诞节倒计时

我一直在尝试为android应用程序创建一个圣诞节倒计时的代码

这就是我目前所拥有的

      Calendar thatDay = Calendar.getInstance();
      thatDay.setTime(new Date(0)); /* reset */
      thatDay.set(Calendar.DAY_OF_MONTH, 25);
      thatDay.set(Calendar.MONTH, 11); // 0-11 so 1 less
      thatDay.set(Calendar.YEAR, 2014);

      Calendar today = Calendar.getInstance();


     while (true)
     {


     long diff = thatDay.getTimeInMillis() - today.getTimeInMillis();
     long diffSec = diff / 1000;

     long days = diffSec / SECONDS_IN_A_DAY;
     long secondsDay = diffSec % SECONDS_IN_A_DAY;
     long seconds = secondsDay % 60;
     long minutes = (secondsDay / 60) % 60;
     long hours = (secondsDay / 3600); // % 24 not needed

  }

然而，当我尝试循环它时，它会产生太多的输出。如何显示每秒更新的代码

请帮忙

你的循环

while (true) {
    ...
}

永远不要终止，因为你没有

中断在它里面

相反，请尝试一个
for
循环：

import java.text.SimpleDateFormat;
import java.util.concurrent.TimeUnit;

SimpleDateFormat f = new SimpleDateFormat("yyyy-MM-dd");
Date xmas = f.parse("2014-12-25");
for (long i = System.currentTimeMillis(); i < xmas.getTime(); i += TimeUnit.HOURS.toMillis(1)) { 
    long hours = TimeUnit.MILLISECONDS.toHours(xmas.getTime() - i);
    // do something with hours
}

import java.text.simpleDataFormat；
导入java.util.concurrent.TimeUnit；
SimpleDataFormat f=新的SimpleDataFormat（“yyyy-MM-dd”）；
日期xmas=f.parse（“2014-12-25”）；
对于（long i=System.currentTimeMillis（）；i

这个循环会持续几个小时直到圣诞节，但是你可以很容易地改变它

请注意使用类而不是大量的数学运算。
如果使用ScheduledExecutorService，则最好使用该服务，该服务将重复执行，直到到达目标时间为止。
它的优点是在打印输出之间不使用处理器时间

    final ScheduledExecutorService service = new ScheduledThreadPoolExecutor(1);
    final Calendar thatDay = new GregorianCalendar(2014, 11, 25);
    final Calendar today = Calendar.getInstance();
    service.schedule(new Runnable() {

        @Override
        public void run() {
            long diff = thatDay.getTimeInMillis() - today.getTimeInMillis();
            long diffSec = diff / 1000;
            long days = diffSec / SECONDS_IN_A_DAY;
            long secondsDay = diffSec % SECONDS_IN_A_DAY;
            long seconds = secondsDay % 60;
            long minutes = (secondsDay / 60) % 60;
            long hours = (secondsDay / 3600); // % 24 not needed
            if (diff > 0) {
                ses2.schedule(this, 1, TimeUnit.SECONDS);
            }
        }
    }, 1, TimeUnit.SECONDS);

甚至在圣诞节之后；）轻微的打字错误，
i
尖锐的物体在java中是危险的。@compass是的，我在iPhone上翻代码时有点打字错误。修正了，谢谢波希米亚人！我在爪哇是个十足的傻瓜！我试着输入代码，但编译器运行起来有困难。有什么想法吗？谢谢