Java 起初它说我的输出代码无法访问，现在它说有一个错误。有人能帮我找出我的错误在哪里吗？_Java

Java 起初它说我的输出代码无法访问，现在它说有一个错误。有人能帮我找出我的错误在哪里吗？

java

Java 起初它说我的输出代码无法访问，现在它说有一个错误。有人能帮我找出我的错误在哪里吗？,java,Java,如果我删除了它建议我删除的令牌，那么我将出现另一个错误“代码不可访问” 这是我的密码： public class finalgrade { public static void main(String[] args) { // TODO Auto-generated method stub Scanner in = new Scanner(System.in); //Input device scanner doubl

如果我删除了它建议我删除的令牌，那么我将出现另一个错误“代码不可访问”

这是我的密码：

public class finalgrade {

    public static void main(String[] args) 
    {
        // TODO Auto-generated method stub

        Scanner in = new Scanner(System.in);    //Input device scanner

        double n = 0.0;     //counter
        double m = 0.0;     //counter
        double x = 0.0;     //counter
        double y = 0.0;     //counter
        double s = 0.0;     //counter

        double totalgrade;

//input 

        String first_name;              //Holds first name 
        System.out.print("Enter your first name: ");
        first_name = in.next();

        String last_name;               //Holds last name 
        System.out.print("Enter your last name: ");
        last_name = in.next();

        String major;                   //Holds user's major
        System.out.print("Enter your intended major: ");
        major = in.next();

        String ist;                     //Holds user's class number
        System.out.print("Enter the IST class you are in: ");
        ist = in.next();

        //Holds user's number grade
        System.out.print("Enter one of five grades: ");
        n = in.nextDouble();

        //Holds user's number grade
        System.out.print("Enter another grade: ");
         m = in.nextDouble();

         //Holds user's number grade
         System.out.print ("Enter another grade: ");
         x = in.nextDouble();

         //Holds user's number grade
         System.out.print("Enter another grade: ");
         y = in.nextDouble();

         //Holds user's number grade
         System.out.print("Enter another grade: ");
         s = in.nextDouble();

//processes 

        totalgrade = n + m + x + y + s / 5;                 //determines the average of grades

         int gradePercent = (int)Math.round(totalgrade);    //converts double to integer

            String grade;
            switch (gradePercent/10)                        //converts integer to string
            {
            case 6 : grade = "D"; break;
            case 7 : grade = "C"; break;
            case 8 : grade = "B"; break;
            case 9 :grade = "A"; break;
            default: grade = "F"; break;


//output

    System.out.println("First Name: " + first_name + "Last Name: " + last_name + "Major: " + major + "IST Class: " + ist + "Average Grade: " + totalgrade+ "%" "Letter Grade: " + grade ".");

            }


    }}

****Eclipse说删除“字母等级：”和“.”，但当我删除它时，它说不可访问

变化

   int gradePercent = (int)Math.round(totalgrade);    //converts double to integer

        String grade;
        switch (gradePercent/10)                        //converts integer to string
        {
        case 6 : grade = "D"; break;
        case 7 : grade = "C"; break;
        case 8 : grade = "B"; break;
        case 9 :grade = "A"; break;
        default: grade = "F"; break;


 System.out.println("First Name: " + first_name + "Last Name: " + last_name + "Major: " + major + "IST Class: " + ist + "Average Grade: " + totalgrade+ "%" "Letter Grade: " + grade ".");
}

将来

这修复了串联问题和无法访问的代码，因为in位于开关块内部。

更改

   int gradePercent = (int)Math.round(totalgrade);    //converts double to integer

        String grade;
        switch (gradePercent/10)                        //converts integer to string
        {
        case 6 : grade = "D"; break;
        case 7 : grade = "C"; break;
        case 8 : grade = "B"; break;
        case 9 :grade = "A"; break;
        default: grade = "F"; break;


 System.out.println("First Name: " + first_name + "Last Name: " + last_name + "Major: " + major + "IST Class: " + ist + "Average Grade: " + totalgrade+ "%" "Letter Grade: " + grade ".");
}

将来

这修复了串联问题和无法访问的代码，因为in位于开关块内。

您忘记在字母等级前加+了

您的系统输出位于开关/机箱支架内

//output
}
System.out.println("First Name: " + first_name + "Last Name: " + last_name + "Major: " + major + "IST Class: " + ist + "Average Grade: " + totalgrade+ "%" + "Letter Grade: " + grade ".");       
}}

你忘了在字母等级前加+号

您的系统输出位于开关/机箱支架内

//output
}
System.out.println("First Name: " + first_name + "Last Name: " + last_name + "Major: " + major + "IST Class: " + ist + "Average Grade: " + totalgrade+ "%" + "Letter Grade: " + grade ".");       
}}

在switch语句中，如果您在所有情况（包括默认情况）遇到break语句之后写入任何内容，那么编译器将在switch语句中抱怨“无法读取代码”

，如果您在所有情况（包括默认情况）之后写入任何内容遇到break语句时，编译器将抱怨“代码不可读取”

请运行此代码。这运行良好（在我的电脑测试），我希望它将服务于您的目的。你的错误是：

switch语句的右括号放错了位置（这就是SOP语句进入switch块的原因）

SOP语句中的几个连接错误

我已经在代码的相应部分提到了您的错误

public class finalgrade {

public static void main(String[] args) 
{
    // TODO Auto-generated method stub

    Scanner in = new Scanner(System.in);    //Input device scanner

    double n = 0.0;     //counter
    double m = 0.0;     //counter
    double x = 0.0;     //counter
    double y = 0.0;     //counter
    double s = 0.0;     //counter

    double totalgrade;

//input 

    String first_name;              //Holds first name 
    System.out.print("Enter your first name: ");
    first_name = in.next();

    String last_name;               //Holds last name 
    System.out.print("Enter your last name: ");
    last_name = in.next();

    String major;                   //Holds user's major
    System.out.print("Enter your intended major: ");
    major = in.next();

    String ist;                     //Holds user's class number
    System.out.print("Enter the IST class you are in: ");
    ist = in.next();

    //Holds user's number grade
    System.out.print("Enter one of five grades: ");
    n = in.nextDouble();

    //Holds user's number grade
    System.out.print("Enter another grade: ");
     m = in.nextDouble();

     //Holds user's number grade
     System.out.print ("Enter another grade: ");
     x = in.nextDouble();

     //Holds user's number grade
     System.out.print("Enter another grade: ");
     y = in.nextDouble();

     //Holds user's number grade
     System.out.print("Enter another grade: ");
     s = in.nextDouble();

//processes 

    totalgrade = n + m + x + y + s / 5;                 //determines the average of grades

     int gradePercent = (int)Math.round(totalgrade);    //converts double to integer

        String grade;
        switch (gradePercent/10)                        //converts integer to string
        {
        case 6 : grade = "D"; break;
        case 7 : grade = "C"; break;
        case 8 : grade = "B"; break;
        case 9 :grade = "A"; break;
        default: grade = "F"; break;
        }   //---------switch statement was not closed properly-------------

//output

System.out.println("First Name: " + first_name + "Last Name: " + last_name + "Major: " + major + "IST Class: " + ist + "Average Grade: " + totalgrade + "%" + "Letter Grade: " + grade + ".");

//---------several concatenation problems were in the SOP---------        


}}

请运行此代码。这运行良好（在我的电脑测试），我希望它将服务于您的目的。你的错误是：

switch语句的右括号放错了位置（这就是SOP语句进入switch块的原因）

SOP语句中的几个连接错误

我已经在代码的相应部分提到了您的错误

public class finalgrade {

public static void main(String[] args) 
{
    // TODO Auto-generated method stub

    Scanner in = new Scanner(System.in);    //Input device scanner

    double n = 0.0;     //counter
    double m = 0.0;     //counter
    double x = 0.0;     //counter
    double y = 0.0;     //counter
    double s = 0.0;     //counter

    double totalgrade;

//input 

    String first_name;              //Holds first name 
    System.out.print("Enter your first name: ");
    first_name = in.next();

    String last_name;               //Holds last name 
    System.out.print("Enter your last name: ");
    last_name = in.next();

    String major;                   //Holds user's major
    System.out.print("Enter your intended major: ");
    major = in.next();

    String ist;                     //Holds user's class number
    System.out.print("Enter the IST class you are in: ");
    ist = in.next();

    //Holds user's number grade
    System.out.print("Enter one of five grades: ");
    n = in.nextDouble();

    //Holds user's number grade
    System.out.print("Enter another grade: ");
     m = in.nextDouble();

     //Holds user's number grade
     System.out.print ("Enter another grade: ");
     x = in.nextDouble();

     //Holds user's number grade
     System.out.print("Enter another grade: ");
     y = in.nextDouble();

     //Holds user's number grade
     System.out.print("Enter another grade: ");
     s = in.nextDouble();

//processes 

    totalgrade = n + m + x + y + s / 5;                 //determines the average of grades

     int gradePercent = (int)Math.round(totalgrade);    //converts double to integer

        String grade;
        switch (gradePercent/10)                        //converts integer to string
        {
        case 6 : grade = "D"; break;
        case 7 : grade = "C"; break;
        case 8 : grade = "B"; break;
        case 9 :grade = "A"; break;
        default: grade = "F"; break;
        }   //---------switch statement was not closed properly-------------

//output

System.out.println("First Name: " + first_name + "Last Name: " + last_name + "Major: " + major + "IST Class: " + ist + "Average Grade: " + totalgrade + "%" + "Letter Grade: " + grade + ".");

//---------several concatenation problems were in the SOP---------        


}}

字符串串联的最后一部分缺少一个

。输出应该放在

开关的外部。它必须是“字母级：“+Grade+”）
我会说“平均分数：”+totalgrade+“%”“字母分数：”
这里应该是“+
”（加上“
”）这里“%”+“字母…
”。或者你应该把“
放在%之后和字母之前。在做了这些修改之后，它表示无法访问的代码字符串串联的最后一部分缺少了一个++
。并且输出应该放在开关的外部。它需要是“字母级：“+Grade+”）
我会说“平均分数：”+totalgrade+“%”“字母分数：”
这里应该是“+
”（加上“
”）这里“%”+“字母…
”。或者你应该把“
在%之后和字母之前删除。在做了这些修改之后，它会说是“无法访问的代码”