Java 在character'上没有可行的替代方案&书信电报；EOF>'；在我的语法中

我正在尝试为SRT格式创建语法：

以下是srt文件的一个示例：

1
00:00:02,218 --> 00:00:04,209
[SHELDON SPEAKING IN MANDARIN]

2
00:00:04,721 --> 00:00:05,745
No, it's:

3
00:00:05,922 --> 00:00:07,913
[SPEAKING IN MANDARIN]

4
00:00:09,392 --> 00:00:11,383
[SPEAKING IN MANDARIN]

5
00:00:13,430 --> 00:00:15,193
What's this?

6
00:00:16,266 --> 00:00:18,029
That's what you did.

7
00:00:18,201 --> 00:00:22,467
I assumed, as in a number of languages,
that the gesture was part of the phrase.

8
00:00:22,639 --> 00:00:25,233
- Well, it's not.
- Why am I supposed to know that?

9
00:00:25,408 --> 00:00:28,900
As teacher, it's your obligation
to separate your personal idiosyncrasies...

10
00:00:29,079 --> 00:00:30,512
...from the subject matter.

11
00:00:31,081 --> 00:00:33,845
- I'm glad you decided to learn Mandarin.
- Why?

326
00:18:56,818 --> 00:19:00,720
Actually, I've heard
far too much about Schrödinger's cat.

327
00:19:01,623 --> 00:19:03,022
Good.

328
00:19:09,131 --> 00:19:11,895
All right, the cat's alive.
Let's go to dinner.

329
00:19:12,000 --> 00:19:15,072
Download Movie Subtitles Searcher from www.OpenSubtitles.org

这是我的antlr语法（3.4节）

我的简单代码：

String input = IOUtils.toString(Test.class.getResourceAsStream("/subtitles.srt"));
ExpLexer lexer = new ExpLexer(new ANTLRStringStream(input));
CommonTokenStream stream = new CommonTokenStream(lexer);
ExpParser parser = new ExpParser(stream);
parser.parse();

如果在文件末尾有两行新行，几乎所有的东西都能完美地工作。如果没有，我会得到这个错误：

line 1484:0 no viable alternative at character '<EOF>'

第1484:0行字符“”处没有可行的替代方案

---

有什么建议可以让我的语法更灵活吗？接受最后会有一行、两行或更多行

原因是

TEXT

需要在末尾添加两行新行

您可以尝试从

文本

中删除一个尾随NL，并将其作为

字幕

之间的分隔符

比如：

parse
    :  SUBTITLE (NL SUBTITLE)*
    ;

---

顺便说一句，文本只能有一行或两行吗？

原因是

TEXT

需要在末尾添加两行

您可以尝试从

文本

中删除一个尾随NL，并将其作为

字幕

之间的分隔符

比如：

parse
    :  SUBTITLE (NL SUBTITLE)*
    ;

---

顺便说一句，文本只能有一行或两行吗？

您使用的词法规则太多了

试着这样做：

grammar T;

options {
  output=AST;
}

tokens {
  BLOCKS;
  BLOCK;
  TIME_RANGE;
  LINES;
  LINE;
  WORD;
}

parse
 : LineBreak* blocks LineBreak* EOF -> blocks
 ;

blocks
 : block (LineBreak LineBreak+ block)* -> ^(BLOCKS block+)
 ;

block 
 : Number Spaces? LineBreak time_range LineBreak text_lines -> ^(BLOCK Number time_range text_lines)
 ;

time_range
 : Time Spaces? Arrow Spaces? Time Spaces? -> ^(TIME_RANGE Time Time)
 ;

text_lines
 : line (LineBreak line)* -> ^(LINES line+)
 ;

line
 : Spaces? word (Spaces word)* Spaces? -> ^(LINE word+)
 ;

word
 : (Other | Number | Dashes | Arrow)+ -> WORD[$text]
 ;

Time      : Number ':' Number ':' Number ',' Number;
Arrow     : '-->';
Dashes    : '-'+;
Number    : '0'..'9'+;
LineBreak : '\r'? '\n' | '\r';
Spaces    : (' ' | '\t')+;
Other     : . ;

这将解析输入：

1 00:00:02,218 --> 00:00:04,209 [A B C] 2 00:00:04,721 --> 00:00:05,745 -- Line 1 -- Line 2 3 00:00:05,922 --> 00:00:07,913 mu --> MU

---

你用的词法规则太多了

试着这样做：

grammar T;

options {
  output=AST;
}

tokens {
  BLOCKS;
  BLOCK;
  TIME_RANGE;
  LINES;
  LINE;
  WORD;
}

parse
 : LineBreak* blocks LineBreak* EOF -> blocks
 ;

blocks
 : block (LineBreak LineBreak+ block)* -> ^(BLOCKS block+)
 ;

block 
 : Number Spaces? LineBreak time_range LineBreak text_lines -> ^(BLOCK Number time_range text_lines)
 ;

time_range
 : Time Spaces? Arrow Spaces? Time Spaces? -> ^(TIME_RANGE Time Time)
 ;

text_lines
 : line (LineBreak line)* -> ^(LINES line+)
 ;

line
 : Spaces? word (Spaces word)* Spaces? -> ^(LINE word+)
 ;

word
 : (Other | Number | Dashes | Arrow)+ -> WORD[$text]
 ;

Time      : Number ':' Number ':' Number ',' Number;
Arrow     : '-->';
Dashes    : '-'+;
Number    : '0'..'9'+;
LineBreak : '\r'? '\n' | '\r';
Spaces    : (' ' | '\t')+;
Other     : . ;

这将解析输入：

1 00:00:02,218 --> 00:00:04,209 [A B C] 2 00:00:04,721 --> 00:00:05,745 -- Line 1 -- Line 2 3 00:00:05,922 --> 00:00:07,913 mu --> MU

---

你好，巴特，谢谢你的回复。当文本中的数字和冒号时，我有一些问题第1季第15集：“或”“我会在11:00给你打电话。维多利亚。”“试图修改你的示例，但没有成功。@克里斯，没问题，请检查我的编辑。你好，巴特，谢谢你的回复。”。当文本中的数字和冒号时，我有一些问题第1季第15集：“或”“我会在11:00给你打电话。维多利亚。”“试图修改你的示例，但没有成功。@克里斯，没问题，请检查我的编辑。”。