从文本文件中读取整数并将其放入2D数组(Java)
我有一个包含整数的文本文件:从文本文件中读取整数并将其放入2D数组(Java),java,arrays,parseint,Java,Arrays,Parseint,我有一个包含整数的文本文件: 6 3 4 15 9 5 14 8 12 0 1 10 13 11 7 2 (全部用空格隔开) 我需要使用扫描仪读取这些数据,然后将它们放入4x4矩阵中 state = new int [sizeOfPuzzle][sizeOfPuzzle]; isSolved = false; IODialog input = new IODialog(); String location = input.readLine("En
6 3 4 15
9 5 14 8
12 0 1 10
13 11 7 2
(全部用空格隔开)
我需要使用扫描仪读取这些数据,然后将它们放入4x4矩阵中
state = new int [sizeOfPuzzle][sizeOfPuzzle];
isSolved = false;
IODialog input = new IODialog();
String location = input.readLine("Enter the full path of the configuration text file: ");
File temp = new File (location);
Scanner file = new Scanner (temp);
while (file.hasNextInt())
{
int x=0;
for (int i=0; i<sizeOfPuzzle; i++)
{
for (int j=0; j<sizeOfPuzzle; j++)
{
state[i][j]=x;
x++;
}
}
}
state=newint[sizeOfPuzzle][sizeOfPuzzle];
isSolved=false;
IODialog输入=新的IODialog();
String location=input.readLine(“输入配置文本文件的完整路径:”);
文件温度=新文件(位置);
扫描仪文件=新扫描仪(临时);
while(文件.hasNextInt())
{
int x=0;
对于(int i=0;i要从文件中读取,请使用扫描仪的nextInt()
方法更改x
for (int i=0; i<sizeOfPuzzle; i++){
for (int j=0; j<sizeOfPuzzle; j++){
state[i][j]=sc.nextInt();
//Choose a good name for Scanner object like sc instead of file
}
}
对于(int i=0;i要从文件中读取,请使用扫描仪的nextInt()方法更改x
for (int i=0; i<sizeOfPuzzle; i++){
for (int j=0; j<sizeOfPuzzle; j++){
state[i][j]=sc.nextInt();
//Choose a good name for Scanner object like sc instead of file
}
}
对于(int i=0;i要从文件中读取,请使用扫描仪的nextInt()方法更改x
for (int i=0; i<sizeOfPuzzle; i++){
for (int j=0; j<sizeOfPuzzle; j++){
state[i][j]=sc.nextInt();
//Choose a good name for Scanner object like sc instead of file
}
}
对于(int i=0;i要从文件中读取,请使用扫描仪的nextInt()方法更改x
for (int i=0; i<sizeOfPuzzle; i++){
for (int j=0; j<sizeOfPuzzle; j++){
state[i][j]=sc.nextInt();
//Choose a good name for Scanner object like sc instead of file
}
}
for(int i=0;i为什么要递增x而不是从扫描仪读取?为什么要递增x而不是从扫描仪读取?为什么要递增x而不是从扫描仪读取?为什么要递增x而不是从扫描仪读取?