Java 使用SpringJPA和eclipseLink，UUID作为Id绑定在查询中作为对象引用

我正在尝试使用Spring和JPA。我在Oracle中有一个表，其中很少有字段是原始（16字节）类型的。我的实体如下所示：

@Entity
@Table(name = "testTable")
public class TestTable implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    @Column(name = "ID")
    @Type(type = "uuid-binary")
    private UUID id;

    @Column(name = "TABLE_ID")
    @Type(type = "uuid-binary")
    private UUID tableId;

    @Column(name = "STATUS")
    private String status;

@Repository
public interface TestRepository extends JpaRepository<TestTable, UUID> {

    TestTable getTestTableByTableId(@Param("table_id") UUId table_id);
}

我的存储库类如下所示：

@Entity
@Table(name = "testTable")
public class TestTable implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    @Column(name = "ID")
    @Type(type = "uuid-binary")
    private UUID id;

    @Column(name = "TABLE_ID")
    @Type(type = "uuid-binary")
    private UUID tableId;

    @Column(name = "STATUS")
    private String status;

@Repository
public interface TestRepository extends JpaRepository<TestTable, UUID> {

    TestTable getTestTableByTableId(@Param("table_id") UUId table_id);
}

当我在控制器中自动连接存储库并调用存储库中定义的方法时，JPA在后台创建SQL并尝试绑定参数，但它绑定的是对象引用而不是UUID，如下所示：

@Configuration
@EnableTransactionManagement
@EnableJpaRepositories(basePackageClasses = { TestRepository.class })
@EnableJpaAuditing
public class JpaConfig {

    @Bean(name="entityManagerFactory")
    public LocalContainerEntityManagerFactoryBean entityManagerFactoryBean() {

        Map<String, Object> jpaProperties = new HashMap<>();
        jpaProperties.put("eclipselink.weaving", "false");
        jpaProperties.put("eclipselink.logging.parameters", "true");

        LocalContainerEntityManagerFactoryBean entityManagerFactoryBean = new LocalContainerEntityManagerFactoryBean();
        entityManagerFactoryBean.setDataSource(this.getDataSource());
        entityManagerFactoryBean.setPackagesToScan("com.test.entity");
        entityManagerFactoryBean.setLoadTimeWeaver(new InstrumentationLoadTimeWeaver());
        entityManagerFactoryBean.setJpaVendorAdapter(this.vendorAdapter());
        entityManagerFactoryBean.setJpaPropertyMap(jpaProperties);

        return entityManagerFactoryBean;
    }

    @Bean
    public JpaVendorAdapter vendorAdapter() {
        EclipseLinkJpaVendorAdapter vendorAdapter = new EclipseLinkJpaVendorAdapter();
        vendorAdapter.setDatabase(Database.ORACLE);
        vendorAdapter.setShowSql(true);

        return vendorAdapter;
    }

    @Bean
    public PersistenceExceptionTranslationPostProcessor exceptionTranslation() {
        return new PersistenceExceptionTranslationPostProcessor();
    }

    @Bean
    public DriverManagerDataSource getDataSource() {
        DriverManagerDataSource dataSource = new DriverManagerDataSource();
    //datasource properties here

        return dataSource;
    }

    @Bean()
    public PlatformTransactionManager transactionManager() {
        JpaTransactionManager transactionManager = new JpaTransactionManager();
        transactionManager.setEntityManagerFactory(this.entityManagerFactoryBean().getObject());

        return transactionManager;
    }

[EL Fine]: sql: 2016-08-10 09:17:22.306--ServerSession(1292029763)--Connection(678757862)--SELECT ID, TABLE_ID, STATUS FROM TESTTABLE WHERE (TABLE_ID= ?)
    bind => [[B@2f6964a4]

---

我的问题是，为什么它要将其作为对象绑定？我该如何解决？提前感谢。

您好，请尝试将类型从uuid binary更改为uuid char。@duardito如您所述更改了类型，仍尝试绑定为对象引用。因此，也许您应该使用varchar type。您将uuid存储为字符串。我以前使用过它，并以varchar的形式存储在DB中。@duardito这就是问题所在，我在DB中有这个字段作为原始（16字节）类型，并且这个配置在

HibernateJavaEndoraptor

中可以很好地工作，只是不能让它与

EclipseLinkJPavendorAdapter