Javascript 谷歌地图API自动完成

Javascript 谷歌地图API自动完成,javascript,google-maps,autocomplete,Javascript,Google Maps,Autocomplete,我使用的是谷歌地图API自动完成(PlacesAPI)和JavaScript 输入3个字符后如何运行自动完成 这是我的代码: function initAutocomplete() { var input = $('#autocomplete')[0]; var autocomplete = new google.maps.places.Autocomplete(input); autocomplete.addListener('place_changed', {

我使用的是谷歌地图API自动完成(PlacesAPI)和JavaScript

输入3个字符后如何运行自动完成

这是我的代码:

function initAutocomplete() {
    var input = $('#autocomplete')[0];

    var autocomplete = new google.maps.places.Autocomplete(input);
    autocomplete.addListener('place_changed', {
        gPlace = autocomplete.getPlace();
    });

    var _addEventListener = (input.addEventListener) ? input.addEventListener : input.attachEvent;

    function addEventListenerWrapper(type, listener) {
        if (type == "keydown") {
            var orig_listener = listener;

            listener = function(event) {
                var suggestion_selected = $(".pac-item-selected").length > 0;

                if (event.which == 13 && !suggestion_selected) {
                    var simulated_downarrow = $.Event("keydown", {keyCode:40, which:40})
                    orig_listener.apply(input, [simulated_downarrow]);
                }

                orig_listener.apply(input, [event]);
            };
        }
        _addEventListener.apply(input, [type, listener]);
    }

    if (input.addEventListener) {
        input.addEventListener = addEventListenerWrapper;
    } else if (input.attachEvent) {
        input.attachEvent = addEventListenerWrapper;
    }
}
我希望我能把我的问题解释清楚。
提前感谢。

您可以参考以下方法在3个字符后使用Google Maps API自动完成功能:

function initAutocomplete() {
    var input = $('#autocomplete')[0];

    var autocomplete = new google.maps.places.Autocomplete(input);
    autocomplete.addListener('place_changed', {
        gPlace = autocomplete.getPlace();
    });

    var _addEventListener = (input.addEventListener) ? input.addEventListener : input.attachEvent;

    function addEventListenerWrapper(type, listener) {
        if (type == "keydown") {
            var orig_listener = listener;

            listener = function(event) {
                var suggestion_selected = $(".pac-item-selected").length > 0;

                if (event.which == 13 && !suggestion_selected) {
                    var simulated_downarrow = $.Event("keydown", {keyCode:40, which:40})
                    orig_listener.apply(input, [simulated_downarrow]);
                }

                orig_listener.apply(input, [event]);
            };
        }
        _addEventListener.apply(input, [type, listener]);
    }

    if (input.addEventListener) {
        input.addEventListener = addEventListenerWrapper;
    } else if (input.attachEvent) {
        input.attachEvent = addEventListenerWrapper;
    }
    return false;
}

谢谢,但此方法在只有一个字符后运行。还有其他想法吗?