如何使用变量到达JavaScript对象中的某个位置?
我有一个名为“winners”的JavaScript对象,如下所示:如何使用变量到达JavaScript对象中的某个位置?,javascript,object,Javascript,Object,我有一个名为“winners”的JavaScript对象,如下所示: var winners = { rock: { "scissors": true, "paper": false } paper: { "rock": true, "scissors": false } scissors: { "rock": false, "paper": true
var winners = {
rock: {
"scissors": true,
"paper": false
}
paper: {
"rock": true,
"scissors": false
}
scissors: {
"rock": false,
"paper": true
}
}
我让用户玩,也让电脑玩。所以要想知道谁赢了,我需要这样做:
var userPlay = "rock";
var cpuPlay = "paper"; //this would be a function but for now lets simply it and just set it to "paper"
var winner = winners[userPlay].cpuPlay;
因此,为了找到计算赢家的价值,我需要这样做:
var userPlay = "rock";
var cpuPlay = "paper"; //this would be a function but for now lets simply it and just set it to "paper"
var winner = winners[userPlay].cpuPlay;
但它总是返回未定义的。显然,
winners[userPlay].paper
是有效的,但是我不知道如何使用变量来达到最后的位置。我需要获取cpuPlay本身的值并使用它吗?您的属性名存储在名为cpuPlay
的变量中
var cpuPlay = "paper";
要访问属性,必须使用括号表示法:
var winner = winners[userPlay][cpuPlay];
这很有效,谢谢!只要它允许,我就接受。@DaneelRakow,不客气!别忘了接受答案。