Javascript 提交按钮赢得';t触发器ajax函数
我的代码有一些问题,我试图将我的表单函数分离到另一个php文件,并使用ajax函数根据ID调用表单。但是,在我分离表单函数之后,submit按钮无法调用ajax函数 下面是我用来触发ajax函数并将表单从另一个php显示到shandor.php的shandor.php示例代码:Javascript 提交按钮赢得';t触发器ajax函数,javascript,php,jquery,ajax,Javascript,Php,Jquery,Ajax,我的代码有一些问题,我试图将我的表单函数分离到另一个php文件,并使用ajax函数根据ID调用表单。但是,在我分离表单函数之后,submit按钮无法调用ajax函数 下面是我用来触发ajax函数并将表单从另一个php显示到shandor.php的shandor.php示例代码: <!-- Ajax show form function--> <script> function showSponsor(str) { if (str == "") {
<!-- Ajax show form function-->
<script>
function showSponsor(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET","getSponsorForm.php?sponsor="+str,true);
xmlhttp.send();
}
}
</script>
我做错了什么?请引导我完成。谢谢:)尝试将表单数据序列化 然后
$.get('/url', serializedData, callback);
即:
脚本不应该返回带有
和
的文档,因为您正在将其放入
元素的内部HTML
。您的意思是我应该从getSponsorForm.php中删除body和head标记吗?我应该用哪行代码替换?谢谢
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<?php
$q = intval($_GET['sponsor']);
include 'dbConnection.php';
global $dbLink;
$query="SELECT * FROM sponsor_item WHERE sponsor_item_id = '".$q."'";
$result = $dbLink->query($query);
// Numeric array
while($row=mysqli_fetch_array($result,MYSQLI_ASSOC)){
echo '
<!--Banner Item No 1 Start-->
<div class="box box-primary1">
<div class="box-header">
<h3 class="box-title">Edit Sponsor No.'.$row["sponsor_item_id"].' <small>编辑器</small></h3>
</div>
<div class="box-body">
<form class="form" id="form" action="" method="POST" enctype="multipart/form-data">
<div class="box-body">
<input type="hidden" name="sponsor_id" value="'.$row["sponsor_item_id"].'"></input>
<div class="form-group" >
<label for="sponsorTitle">Sponsor Title 赞助称号</label>
<input type="text" class="form-control" name="sponsorTitle" id="sponsorTitle" placeholder="Please Enter Name" onChange="checkDisabled(testing);">
</div>
<div class="form-group" >
<label for="sponsorDescription">Sponsor Description 赞助描述</label>
<input type="text" class="form-control" name="sponsorDescription" id="sponsorDescription" placeholder="Please Enter Name" onChange="checkDisabled(testing);">
</div>
<div class="form-group">
<label for="exampleInputFile">File input</label>
<input type="file" id="uploaded_file" name="uploaded_file" onChange="checkDisabled(testing);"><br>
<p class="help-block">Your picture size not more than 2MB. (Only JPEG or JPG is allowed)</p>
</div>
<div class="checkbox">
<button id="testing" type="submit" class="btn btn-primary">Update</button>
</div>
</div><!-- /.box-body -->
</form> <!-- Date range -->
<!-- /.form group -->
<!-- Date and time range -->
<!-- /.form group -->
<!-- Date and time range -->
<!-- /.form group -->
</div><!-- /.box-body -->
</div><!-- /.box -->
<!--Banner Item No 1 End-->';
}
mysqli_free_result($result);
// Close the mysql connection
$dbLink->close();
?>
</body>
</html>
//File and text upload with formDATA function
$("form#form").submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url:'sponsorItem.php',
type: 'POST',
data: formData,
async: false,
beforeSend: function(){
if(confirm('Are you sure?'))
return true;
else
return false;
},
cache: false,
contentType: false,
processData: false
}).done(function () {
//do something if you want when the post is successfully
if(!alert('Banner Had Successfully Updated.')){document.getelementbyclassname('form').reset()}
});
return false;
});
$.get('/url', serializedData, callback);
$( "form#form" ).on( "submit", function( event ) {
event.preventDefault();
var data = $(this).serialize();
$.post('sponsorItem.php', data, function(response){
$('#txtHint').text(response);
});
});