带有聚合键的Javascript数组reduce
我的目标是从如下数组对象：带有聚合键的Javascript数组reduce,javascript,Javascript,我的目标是从如下数组对象： const data = [ { code: 'prod1', quantity: 13, pricePerItem: 10, totalCost: 130 }, { code: 'prod1', quantity: 7, pricePerItem: 11, totalCost: 77 },
const data = [
{
code: 'prod1',
quantity: 13,
pricePerItem: 10,
totalCost: 130
},
{
code: 'prod1',
quantity: 7,
pricePerItem: 11,
totalCost: 77
},
{
code: 'prod2',
quantity: 10,
pricePerItem: 9,
totalCost: 90
},
{
code: 'prod2',
quantity: 9,
pricePerItem: 10,
totalCost: 90
},
];
{
prod1:{
quantity: 20,
total: 207
},
prod2:{
quantity: 19,
total:180
}
}
data.reduce(
(acc, current) => {
return {
total: acc.total + current.totalCost,
quantity: acc.quantity + current.quantity
};
},
{ total: 0, quantity: 0 }
);
您能帮我吗？您可以使用reduce执行以下操作
const res = data.reduce((prev, curr) => {
if(prev.hasOwnProperty(curr.code)) {
prev[curr.code] = {total: prev[curr.code].total + curr.totalCost, quantity: prev[curr.code].quantity + curr.quantity };
return prev;
} else {
prev[curr.code] = {total: curr.totalCost, quantity: curr.quantity };
return prev;
}
}, {});
console.log(res);
您可以使用reduce执行以下操作：
const res = data.reduce((prev, curr) => {
if(prev.hasOwnProperty(curr.code)) {
prev[curr.code] = {total: prev[curr.code].total + curr.totalCost, quantity: prev[curr.code].quantity + curr.quantity };
return prev;
} else {
prev[curr.code] = {total: curr.totalCost, quantity: curr.quantity };
return prev;
}
}, {});
console.log(res);