Javascript 根据当前日期获取日期的名称

我需要能够获得以下信息：

function changeDate(date)
{
   var d = new Date();
   if(d) // check if in the current week
   {
      return date.format(EEE);
   }else if()  //check if out of the week
   {
      return date.format(d MMM);
   }
}

检查我的当前日期是否为本周的周一-周日，如果我在本周，我应该能够返回一个日期名称，格式为三个字母MON-for Monday EEE格式 如果我不在本周，我需要用三个字母的month d MMM格式返回日期，例如3月11日 我尝试了以下方法：

function changeDate(date)
{
   var d = new Date();
   if(d) // check if in the current week
   {
      return date.format(EEE);
   }else if()  //check if out of the week
   {
      return date.format(d MMM);
   }
}

日期的格式为MM/dd/yyyy HH:MM

假设当前日期是指给定日期

试试这个：

function getWeek(d) {                            
  var target  = new Date(d.valueOf());  
  var dayNr   = (d.getDay() + 6) % 7;  
  target.setDate(target.getDate() - dayNr + 3);  
  var jan4    = new Date(target.getFullYear(), 0, 4);    
  var dayDiff = (target - jan4) / 86400000;     
  var weekNr = 1 + Math.ceil(dayDiff / 7);     
  return weekNr;     
}

function changeDate(date) {
   var d = new Date();
   return getWeek(d) == getWeek(date)? 
          date.toString().substring(0,3).toUpperCase():
          b.getDate() + " " + b.toString().substring(3,7).toUpperCase();
}

getWeek是从哪里来的

示例用法：

var a = new Date("Feb 14 2014"),  
    b = new Date("Mar 15 2014");

changeDate(a);               // "FRI"

changeDate(b);               // "15  MAR"

此方法getCalWeek将为您提供一个对象，其中包含给定日期的周和年

function thursday(mydate) {
  var Th=new Date();
  Th.setTime(mydate.getTime() + (3-((mydate.getDay()+6) % 7)) * 86400000);
  return Th;
}

function getCalWeek(thedate) {
    ThursDate=thursday(thedate);
    weekYear=ThursDate.getFullYear();
    ThursWeek1=thursday(new Date(weekYear,0,4));
    theweek=Math.floor(1.5+(ThursDate.getTime()-ThursWeek1.getTime())/86400000/7);
    return {"week": theweek, "year" : weekYear};
}

然后您可以比较两个日期的周和年

var weekdays = ["SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT"];
var months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"];

function changeDate(date) {
   d = new Date(); // today
   weekAndYearToday = getCalWeek(d);
   weekAndYearDate = getCalWeek(date);
   if(weekAndYearToday.week = weekAndYearDate.week && weekAndYearToday.year = weekAndYearDate.year) {
      // here it is clear that "date" is in the current week
      return weekdays[date.getDay()];
   } else {
      return date.getDate() + " " + months[date.getMonth()];
   }
}

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当您提供验证日期和测试周时，下面的代码应该为您提供所需的日期

它已经过单元测试

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您当前的日期一定是当前的一周吗？你可能没有解释清楚-你能举个例子说明你认为这是错误的吗？听起来像是算法问题。。