Javascript 如何在selectize plugin from controller中选择多个值

Javascript 如何在selectize plugin from controller中选择多个值,javascript,arrays,angularjs,object,selectize.js,Javascript,Arrays,Angularjs,Object,Selectize.js,如何添加所选的几个选项 我正在使用这个插件: 我有一个对象,如下图所示: 这是我的客户脚本 //skills $scope.$selectSkill = $('#selectSkill').selectize({ valueField: 'id', labelField: 'name', searchField: 'name', placeholder: "Select Skills", options: $scope.data.skills,

如何添加所选的几个选项 我正在使用这个插件:

我有一个对象,如下图所示:

这是我的客户脚本

//skills
$scope.$selectSkill = $('#selectSkill').selectize({
    valueField: 'id',
    labelField: 'name',
    searchField: 'name',
    placeholder: "Select Skills",
    options: $scope.data.skills,
    create: false,
    sortField: {
        field: 'name',
        direction: 'asc'
    }
});
这是我的HTML

<select id="selectSkill" 
name="selectSkill" 
ng-model="selectSkill" 
multiple required> </select>
我希望这两个被选中,如下图所示

我该怎么做

我试过这样的方法:

var $select = $("#selectSkill").selectize();
                var yourDefaultIds = [slectedSkills.skills];  //(those 2 vlaues)
                selectize.setValue(yourDefaultIds);;
这应该行得通,我已经测试过了。 将这两个值转换为数组,然后设置,而不是设置为字符串

var $select = $("#selectSkill").selectize();
                var yourDefaultIds = [slectedSkills.skills];  //(those 2 vlaues)
                selectize.setValue(yourDefaultIds);;
//populate skills starts here
var templateSkills = finTempObj.skills;
var str_array_skills = templateSkills.split(',');
var $select =   $("#selectSkill").selectize();
var selectize = $select[0].selectize;
selectize.setValue(str_array_skills);
selectize.refreshOptions();
//populate skills ends here