Javascript 如何迭代保存控制器中对象数组的json字符串

我在jsp中将对象数组转换为json字符串，如下所示

$("#submitButton").click(function(){

        var sample = new Array();

           var k = 1;
            for(var i=0; i < JSONObj.length; i++){ 

               var remarkString = $("#eduRemark"+k).val();
               var scoreNum = $("#eduScore"+k).val();

               var objectInfo = {"iqrQuestionRemark":remarkString, "iqrQuestionScore":scoreNum,"crtnByUmId":""};
               sample.push(objectInfo);

                k++;
            } 

        var ArrayData = JSON.stringify(sample);
         alert("Json Data:"+ArrayData); 

            $.ajax({
                  type: "POST",
                  contentType : 'application/json; charset=utf-8',
                  dataType : 'json',
                  url: "/Vidyasaarathi/ipusers/submitAssessmentform",
                  data: ArrayData, 
                  success :function(result) {

                            }
                });


        });

现在我的问题是如何在控制器端分别迭代这个对象数组。

这是我的控制器代码

@RequestMapping(value={VspCommonConstants.INTERVIEW_PANEL_MANAGER_URL+"/submitAssessmentform"}, method = RequestMethod.POST)
    public String submitAssessmentform(@RequestBody List<InterviewQuestionResult> ArrayData,HttpServletRequest request,Model model) throws JsonParseException, JsonMappingException, IOException
    {

        ObjectMapper mapper = new ObjectMapper();
        //String [] actualData = mapper.readValue(ArrayData, String[].class);
        //System.out.println("Json converted Data:"+actualData);
        System.out.println("Result object:"+ArrayData);
        String view = null;

        try {
            view = "ipsearchForm";
        } catch (Exception e) {
            model.addAttribute("errormsg", "System is busy...... Please try after some time.");

        }
        return view;
    }

@RequestMapping（值={VspCommonConstants.INTERVIEW\u PANEL\u MANAGER\u URL+“/submitasessmentform”}，method=RequestMethod.POST）
公共字符串submitAssessMemform（@RequestBody List ArrayData，HttpServletRequest请求，模型模型）抛出JsonParseException、JsonMappingException、IOException
{
ObjectMapper mapper=新的ObjectMapper（）；
//String[]actualData=mapper.readValue（ArrayData，String[].class）；
//System.out.println（“Json转换数据：+actualData”）；
System.out.println（“结果对象：+ArrayData”）；
字符串视图=null；
试一试{
view=“ipsearchForm”；
}捕获（例外e）{
addAttribute（“errormsg”，“系统正忙……请稍后再试。”）；
}
返回视图；
}

---

请提出一些可能的方法。在这里，我试图将json字符串分配给“InterviewQuestionResult”bean，它有一个getter setter。提前谢谢。

你能把你的面试问题结果也粘贴上去吗？从技术上讲，您不需要做任何特殊的事情，如果bean正确映射了您的属性和json结构，那么bean应该由spring自动填充

@RequestMapping(value={VspCommonConstants.INTERVIEW_PANEL_MANAGER_URL+"/submitAssessmentform"}, method = RequestMethod.POST)
    public String submitAssessmentform(@RequestBody List<InterviewQuestionResult> ArrayData,HttpServletRequest request,Model model) throws JsonParseException, JsonMappingException, IOException
    {

        ObjectMapper mapper = new ObjectMapper();
        //String [] actualData = mapper.readValue(ArrayData, String[].class);
        //System.out.println("Json converted Data:"+actualData);
        System.out.println("Result object:"+ArrayData);
        String view = null;

        try {
            view = "ipsearchForm";
        } catch (Exception e) {
            model.addAttribute("errormsg", "System is busy...... Please try after some time.");

        }
        return view;
    }