Javascript MongoDB+中仅按日期分组(不含时间);NodeJS
假设我们有一个查询:Javascript MongoDB+中仅按日期分组(不含时间);NodeJS,javascript,node.js,mongodb,group-by,Javascript,Node.js,Mongodb,Group By,假设我们有一个查询: EightWeekGamePlan.aggregate( [ { $group: { _id: { LeadId: "$LeadId", Week: "$Week", InsertDate: "$InsertDate" , // I want to group by the date part
EightWeekGamePlan.aggregate(
[
{
$group: {
_id: {
LeadId: "$LeadId",
Week: "$Week",
InsertDate: "$InsertDate" , // I want to group by the date part
Status: "$Status"
},
count: { $count: 1 }
}
},
{
$lookup: {
from: "leads",
localField: "_id",
foreignField: "LeadId",
as: "Joined"
}
},
{ $unwind: "$Joined" },
{ $replaceRoot: { newRoot: { $mergeObjects: ["$Joined", "$$ROOT"] } } },
{ $sort: { total: -1 } }
],
function(err, results) {
if (err) {
console.log(err);
}
// ... do some manipulations ...
console.log(_filtered);
return res.json(_filtered);
}
);
我按多个字段分组,只想取插入日期的日期部分,而不考虑时间
我们怎么能做到呢 我相信您的问题在mongodb文档中的年度日期分组下得到了解决: 您必须使用
$dateToString
将日期转换为日期格式的字符串,并将其添加到$group\u id
_id : {$dateToString: { format: "%Y-%m-%d", date: "$InserDate" }}
我希望这有帮助