Javascript 如何重构此代码以消除重复？

出于对枯燥（不要重复）代码的兴趣，我想知道下面给出的代码是否可以以任何方式进行重构。在下面的代码中，您可以看到，我重复了

condition1

和

condition2

的赋值语句，因为在每个if语句的末尾，我进行了不同的函数调用

websocket.onmessage = async(event) => {
    const data = JSON.parse(data)
    let infoFromExternalApi1, infoFromExternalApi2, infoFromExternalApi3

    // Assignments for infoFromExternalApi variables are repeated due to difference in function calls doSomething() and doSomethingElse()
    if (condition1) {
        infoFromExternalApi1 = await getInfoFromExternalApi1()
        infoFromExternalApi2 = await getInfoFromExternalApi2()
        infoFromExternalApi3 = await getInfoFromExternalApi3()

        doSomething()
    }

    if (condition2) {
        infoFromExternalApi1 = await getInfoFromExternalApi1()
        infoFromExternalApi2 = await getInfoFromExternalApi2()
        infoFromExternalApi3 = await getInfoFromExternalApi3()

        doSomethingElse()
    }
}

---

你可能在找

websocket.onmessage = async(event) => {
    const data = JSON.parse(data)
    let infoFromExternalApi1, infoFromExternalApi2, infoFromExternalApi3

    if (condition1 || condition2) {
        infoFromExternalApi1 = await getInfoFromExternalApi1()
        infoFromExternalApi2 = await getInfoFromExternalApi2()
        infoFromExternalApi3 = await getInfoFromExternalApi3()
    }
    if (condition1) {
        doSomething()
    }
    if (condition2) {
        doSomethingElse()
    }
}

---

当然，如果这两个条件都为真，那么这与您的原始代码的工作方式不同，即仅从外部API获取一次信息。

如果只对doSomething和doSomethingElse使用if语句，又如何？您在哪里使用

infoFromExternalApiN

变量？你能发布你的实际代码吗？