Javascript 从对象数组中删除重复元素-es6？_Javascript_Arrays_Ecmascript 6_Duplicates_Javascript Objects

Javascript 从对象数组中删除重复元素-es6？

javascript arrays ecmascript-6

Javascript 从对象数组中删除重复元素-es6？,javascript,arrays,ecmascript-6,duplicates,javascript-objects,Javascript,Arrays,Ecmascript 6,Duplicates,Javascript Objects,我有以下对象数组。我需要做的就是从所有连接器阵列中删除匹配的key-val对 [ { "connector":[ { "name":"CC1" }, { "name":"App1" }, { "name":"CC1

我有以下对象数组。我需要做的就是从所有连接器阵列中删除匹配的key-val对

 [  
       {  
          "connector":[  
             {  
                "name":"CC1"
             },
             {  
                "name":"App1"
             },
             {  
                "name":"CC1"
             },
             {  
                "name":"App2"
             },
             {  
                "name":"CC1"
             },
             {  
                "name":"App3"
             }
          ],
          "connections":[  
             {  
                "source":"CC1",
                "target":"App1"
             },
             {  
                "source":"CC1",
                "target":"App2"
             },
             {  
                "source":"CC1",
                "target":"App3"
             }
          ]
       },
       {  
          "connector":[  
             {  
                "name":"CC1"
             },
             {  
                "name":"App1"
             },
             {  
                "name":"CC1"
             },
             {  
                "name":"App2"
             },
             {  
                "name":"CC1"
             },
             {  
                "name":"App3"
             }
          ],
          "connections":[  
             {  
                "source":"CC1",
                "target":"App1"
             },
             {  
                "source":"CC1",
                "target":"App2"
             },
             {  
                "source":"CC1",
                "target":"App3"
             }
          ]
       },
       {  
          "connector":[  
             {  
                "name":"CC1"
             },
             {  
                "name":"App1"
             },
             {  
                "name":"CC1"
             },
             {  
                "name":"App2"
             },
             {  
                "name":"CC1"
             },
             {  
                "name":"App3"
             }
          ],
          "connections":[  
             {  
                "source":"CC1",
                "target":"App1"
             },
             {  
                "source":"CC1",
                "target":"App2"
             },
             {  
                "source":"CC1",
                "target":"App3"
             }
          ]
       },
       {  
          "connector":[  
             {  
                "name":"CC2"
             },
             {  
                "name":"App2"
             }
          ],
          "connections":[  
             {  
                "source":"CC2",
                "target":"App2"
             }
          ]
       }
    ]

我曾尝试在es6中使用filter、map和spreadable操作符的组合，但尚未找到实现这一点的最佳组合。我想要的输出如下：

 [  
           {  
              "connector":[  
                 {  
                    "name":"CC1"
                 },
                 {  
                    "name":"App1"
                 },
                 {  
                    "name":"App2"
                 },
                 {  
                    "name":"App3"
                 }
              ],
              "connections":[  
                 {  
                    "source":"CC1",
                    "target":"App1"
                 },
                 {  
                    "source":"CC1",
                    "target":"App2"
                 },
                 {  
                    "source":"CC1",
                    "target":"App3"
                 }
              ]
           },
           {  
              "connector":[  
                 {  
                    "name":"CC1"
                 },
                 {  
                    "name":"App1"
                 },
                 {  
                    "name":"App2"
                 },
                 {  
                    "name":"App3"
                 }
              ],
              "connections":[  
                 {  
                    "source":"CC1",
                    "target":"App1"
                 },
                 {  
                    "source":"CC1",
                    "target":"App2"
                 },
                 {  
                    "source":"CC1",
                    "target":"App3"
                 }
              ]
           },
           {  
              "connector":[  
                 {  
                    "name":"CC1"
                 },
                 {  
                    "name":"App1"
                 },
                 {  
                    "name":"App2"
                 },
                 {  
                    "name":"App3"
                 }
              ],
              "connections":[  
                 {  
                    "source":"CC1",
                    "target":"App1"
                 },
                 {  
                    "source":"CC1",
                    "target":"App2"
                 },
                 {  
                    "source":"CC1",
                    "target":"App3"
                 }
              ]
           },
           {  
              "connector":[  
                 {  
                    "name":"CC2"
                 },
                 {  
                    "name":"App2"
                 }
              ],
              "connections":[  
                 {  
                    "source":"CC2",
                    "target":"App2"
                 }
              ]
           }
        ]

实现这一目标的最佳解决方案是什么？提前感谢您的帮助。

setTimeoutdoit，100；函数doit{ data.forEachobj=>{ obj.connector=obj.connector.filter{name}，i，arr=> arr.findIndexo=>o.name==name==i }; 控制台日志数据； } 风险值数据=[{ 连接器：[{ 姓名：CC1 }, { 名称：App1 }, { 姓名：CC1 }, { 姓名:App2 }, { 姓名：CC1 }, { 姓名：App3 } ], 连接：[{ 资料来源：CC1，目标：附件1 }, { 资料来源：CC1，目标：附件2 }, { 资料来源：CC1，目标：附件3 } ] }, { 连接器：[{ 姓名：CC1 }, { 名称：App1 }, { 姓名：CC1 }, { 姓名:App2 }, { 姓名：CC1 }, { 姓名：App3 } ], 连接：[{ 资料来源：CC1，目标：附件1 }, { 资料来源：CC1，目标：附件2 }, { 资料来源：CC1，目标：附件3 } ] }, { 连接器：[{ 姓名：CC1 }, { 名称：App1 }, { 姓名：CC1 }, { 姓名:App2 }, { 姓名：CC1 }, { 姓名：App3 } ], 连接：[{ 资料来源：CC1，目标：附件1 }, { 资料来源：CC1，目标：附件2 }, { 资料来源：CC1，目标：附件3 } ] }, { 连接器：[{ 姓名：CC2 }, { 姓名:App2 } ], 连接：[{ 资料来源：CC2，目标：附件2 }] }

]; 如果您只需要映射、筛选、查找等常见操作，则不需要lodash：

{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{}}}}}}}}}}{{{{{{{{{{{{{{{{名称：}}}}}}}}}}}}}，{{{{{{{{{{{{{{{{{{{{{{{{{名称：名：CC1}}}}}}}}}}}}}}}}}}}}}}}}}{{{{{{{{{{{{}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}目标：CC1，目标：App2}，{source:CC1，target:App3}}，{connector:[{name:CC1}，{name:App1}，{name:CC1}，{name:App2}，{name:CC1}，{name:CC1}，{name:App3}]，connections:[{source:CC1，target:App1}，{source:CC1，target:App2}，{source source:CC1，target:App3}，{connector:[{name:CC2}，{name:App2}，connections:{source； const result=data.mape=>{…e，连接器： e、连接器 //过滤原始连接器阵列 //并仅返回名称为的元素 //与连接源或目标相同 .filterc=>e.connections.findcn=>[cn.source，cn.target].indexOfc.name！=-1 //按名称删除重复项，如@llama notes .filterv，i，ari=>ari.findIndexc=>c.name==v.name==i };

console.logresult这将过滤掉任何重复的对象，连接器和连接对象可以有任意数量的键

mapper = (input) => 
      input.map(x => JSON.stringify(x))          // Stringify
      .filter((x, i, a) => a.indexOf(x) === i)   // Filter out repeating elements
      .map(x => JSON.parse(x))                   // Parse stringified object


output = input.map(item => 
            ({ 
               connector: mapper(item.connector), 
               connections: mapper(item.connections) 
            })
          )

如果您打算使用lodash，请以防万一。这就是您可以做到的方法。u.mapdata，i=>{i.connector=u.uniqByi.connector，'name'；返回i；}最好、最理想的方法是在冗余数据进入此对象数组之前停止冗余数据。您手动从输入数据中删除了重复数据。如果将它们放回，您将看到您的.filter不会删除它们。我想您的意思是，我的代码不会更改原始数据变量，对吗？即int结束。不，我是说您的示例更改了问题中发布的原始数据，以便要删除的重复项不再存在。将它们放回，您将看到您的解决方案不会删除它们。这是因为您的.find回调将为所有重复项返回true…看起来您复制了所需的输出数据我的意思是：所有重复的对象都不会被删除。