Javascript 处理数组中的元素

因此，我有一个名为

match

的数组，其中

match[0]

=

[2014-05-30 15:21:20,781] DEBUG [scheduler-4] (DiamondSchedulerRunner.java:41) Current node is not a manager of:publishEmail in tenant:0 
[2014-05-30 15:21:20,781] DEBUG [scheduler-1] (DiamondSchedulerRunner.java:41) Current node is not a manager of:readEmail in tenant:0 
[2014-06-11 10:18:51,370] ERROR [executorWithPoolSizeRange-5] (PushNotificationsServiceBean.java:140) cannot send notification: service Whaler is not available for user himanshu.taunk@hp.com on device Desktop.device.uuid813374 
[2014-05-30 15:21:50,608] DEBUG [scheduler-3] (DiamondSchedulerProxy.java:96) Diamond Scheduler name:index Mode:TENANT_NODE runOnTenant:true split:true 
[2014-05-30 15:21:50,624] DEBUG [scheduler-3] (DiamondSchedulerRunner.java:41) Current node is not a manager of:index in tenant:0 
[2014-06-11 10:18:49,124] ERROR [executorWithPoolSizeRange-5] (PushNotificationsServiceBean.java:140) cannot send notification: service Whaler is not available for user himanshu.taunk@hp.com on device Desktop.device.uuid798084 
[2014-05-30 15:21:50,780] DEBUG [scheduler-5] (DiamondSchedulerProxy.java:96) Diamond Scheduler name:snooze Mode:TENANT_NODE runOnTenant:true split:true 
[2014-05-30 15:21:50,780] DEBUG [scheduler-5] (DiamondSchedulerRunner.java:41) Current node is not a manager of:snooze in tenant:0 
[2014-05-30 15:21:50,796] ERROR [scheduler-4] (DiamondSchedulerProxy.java:96) Diamond Scheduler name:publishEmail Mode:TENANT_NODE runOnTenant:true split:true 

match[1]

是时间戳，

match[2]

是状态，

match[3]

是线程名称，依此类推。我是否可以反转第一个索引中的元素，

匹配[0]

，使第一行成为最后一行，反之亦然，而不与其他索引混淆

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更好的是，我是否可以逐行将第一个索引读入另一个数组，然后反转后一个数组？

您是否可以使用分隔符拆分匹配[0]，然后进行反转和联接？ i、 e

match[0] = match[0].split('\n').reverse().join('\n')