Javascript 从树中删除所选节点
我正在Angular2应用程序中使用AngularTree组件()显示一棵树 我需要让用户能够选择树中的任何节点并将其删除。这将删除所选节点及其所有子节点(如果是叶节点,则仅删除该节点)。用户完成后,修剪后的树将发送到服务器并保存在那里 在下面的示例中,用户选择“节点1-2”并单击“删除”。这将从视图中删除“节点1-2”、“节点1”和“节点2”,并更新基础Javascript对象。然后,用户可以单击另一个按钮(如保存)将更新的对象保存到服务器上 为了实现这一点,我编写了以下代码,单击Delete按钮即可调用这些代码。我存储所选节点的id,然后遍历整个树以查找该id。当id匹配时,我使用“delete”关键字删除“id”和“text”。但是,“删除子项”不起作用Javascript 从树中删除所选节点,javascript,json,angular,tree,Javascript,Json,Angular,Tree,我正在Angular2应用程序中使用AngularTree组件()显示一棵树 我需要让用户能够选择树中的任何节点并将其删除。这将删除所选节点及其所有子节点(如果是叶节点,则仅删除该节点)。用户完成后,修剪后的树将发送到服务器并保存在那里 在下面的示例中,用户选择“节点1-2”并单击“删除”。这将从视图中删除“节点1-2”、“节点1”和“节点2”,并更新基础Javascript对象。然后,用户可以单击另一个按钮(如保存)将更新的对象保存到服务器上 为了实现这一点,我编写了以下代码,单击Delet
deleteSelectedNode() {
//Get the node which was selected by the user
let nodeToDelete: TreeNode = this.myService.getActiveNode();
//id will be unique, can be used to identify the node
let idToDelete = nodeToDelete.data.id;
this.traverseTree(this.nodes[0], idToDelete);
}
traverseTree(obj, idToDelete: string) {
for (var k in obj) {
if (typeof obj[k] == "object" && obj[k] !== null) {
this.traverseTree(obj[k], idToDelete);
}
else {
if (k === 'id') {
let id = obj[k];
if (id === idToDelete) {
console.log('ID Matched ' + id);
delete obj['id'];
delete obj['text'];
delete obj['children'];
break;
}
}
}
}
}
下面是呈现树的JSON
{
"children": [
{
"children": [
{
"text": "Node 1",
"id": "A493"
},
{
"text": "Node 2",
"id": "A494"
}
],
"text": "Node 1-2",
"id": "A491"
},
{
"children": [
{
"children": [
{
"text": "Node 3",
"id": "A5ab"
},
{
"text": "Node 4",
"id": "A5ac"
},
{
"text": "Node 5",
"id": "A5ad"
},
{
"text": "Node 6",
"id": "A5ae"
},
{
"text": "Node 7",
"id": "A5af"
},
{
"text": "Node 8",
"id": "A5b0"
},
{
"text": "Node 9",
"id": "A5b1"
},
{
"text": "Node 10",
"id": "A5b2"
},
{
"text": "Node 11",
"id": "A5b3"
},
{
"text": "Node 12",
"id": "A5b4"
},
{
"text": "Node 13",
"id": "A6da"
},
{
"text": "Node 14",
"id": "A6db"
}
],
"text": "Node 1-14",
"id": "A495"
},
{
"children": [
{
"text": "Node 15",
"id": "A6dc"
},
{
"text": "Node 16",
"id": "A6dd"
},
{
"text": "Node 17",
"id": "A6de"
},
{
"text": "Node 18",
"id": "A6df"
},
{
"text": "Node 19",
"id": "A6e0"
},
{
"text": "Node 20",
"id": "A6e1"
},
{
"text": "Node 21",
"id": "A6e2"
},
{
"text": "Node 22",
"id": "A6e3"
}
],
"text": "Node 15-22",
"id": "A496"
},
{
"text": "Node 23",
"id": "A497"
},
{
"text": "Node 24",
"id": "A498"
}
],
"text": "Node 23-24",
"id": "A492"
}
],
"text": "Node 1-24",
"id": "A490"
}
如何删除整个节点,包括子节点?还有,有没有更好的方法来实现这一点?您可以通过父级引用轻松地完成这一点
deleteNode() {
let nodeToDelete: TreeNode = this.tree.treeModel.getActiveNode();
if (nodeToDelete.level === 1) {
this.nodes = this.nodes.filter((n) => n.id !== nodeToDelete.id);
} else {
nodeToDelete.parent.children = nodeToDelete.parent.children.filter((n) => n.id !== nodeToDelete.id);
}
}