Javascript 大口喝咖啡+;丑陋的顺序错误
我试图按照特定的顺序压缩和丑化javascript文件。当我禁用丑恶它的工作以及我的命令。但当我打开uglify时,JS顺序被忽略。我做错了什么 脚本_1.jsJavascript 大口喝咖啡+;丑陋的顺序错误,javascript,gulp,gulp-uglify,gulp-concat,Javascript,Gulp,Gulp Uglify,Gulp Concat,我试图按照特定的顺序压缩和丑化javascript文件。当我禁用丑恶它的工作以及我的命令。但当我打开uglify时,JS顺序被忽略。我做错了什么 脚本_1.js let script_one = () => { console.log(1); }; let script_two = () => { console.log(2); }; 脚本_2.js let script_one = () => { console.log(1); }; let scri
let script_one = () => {
console.log(1);
};
let script_two = () => {
console.log(2);
};
脚本_2.js
let script_one = () => {
console.log(1);
};
let script_two = () => {
console.log(2);
};
吞咽任务
gulp.task('js', function() {
return gulp.src(['js/Script1.js', 'js/Script2.js'])
.pipe(rigger())
.pipe(concat('main.js'))
.pipe(babel({presets: ['env']}))
.pipe(uglify())
.pipe(gulp.dest('dist/js'));
});
输出
var script_two=function(){console.log(2)};var script_one=function(){console.log(1)}
预期产出
var script_one=function(){console.log(1)};var script_two=function(){console.log(2)}
不带丑陋的输出
var script_one = function(){
console.log(1)
};
var script_two = function(){
console.log(2)
};
谢谢