Javascript 筛选特定属性并对值求和

我有一个多边形的传单地图，你可以点击每个多边形来选择它们，并且有一个信息窗口“L.control”，显示所选多边形的值。继续单击“多边形”时，“信息”窗口会为每个选定多边形添加值，并获得所有选定多边形的总值。所有这些都很好，但我需要对特定属性进行更详细的汇总，如下面的区域示例。如果选择了十个多边形，我想区分属性为“REGION SOUTH”和“REGION NORTH”的区域的总数以及所有多边形的总数。 这是我正在使用的代码，对不同属性的总和求和没有问题，但是如何对定义的属性求和

如何以及在何处添加一种只对所需属性求和的过滤解决方案

$.each(statesData.features, function(index, feature) {
var name = `${feature.properties.ZIPCODE} ${feature.properties.Name}  ( ${feature.properties.average_time} -  ${feature.properties.CITY})`
placenames.push(name);
zipcodes[name] = feature.properties.ZIPCODE;
time = feature.properties.average_time
});

etc.... 

// Now get the totals of selected polygons
var detailshow = function() {
var result = ''
var total = 0
var total1 = 0
var total2 = 0
var total3 = 0
var total4 = 0
for (var i = 0; i < featuresSelected.length; i++) {

var properties = featuresSelected[i].feature.properties
    result +=
        `
    ${properties.CITY}<br>
    Zipcode: ${properties.ZIPCODE}
    <a href="#" onclick=dellayer(${properties.ZIPCODE})>Delete</a>
    <hr>`;
    total += properties.amount, // sum amount for all regions
    total1 += properties.average_time, // in seconds
    total2 += properties.distance,
    total3 += properties.amount, // amount for Region South only
    total4 += properties.amount, // amount for Region North only

    // Convert seconds to timeformat
    var convertTime = function (input, separator) {
    var pad = function(input) {return input < 10 ? "0" + input : input;};
        return [
        pad(Math.floor(input / 3600)),
        pad(Math.floor(input % 3600 / 60)),
        pad(Math.floor(input % 60)),
        ].join(typeof separator !== 'undefined' ?  separator : ':' );
    }

var resultTime = convertTime(total1);

}
return {
    result: result,
    total: total,
    resultTime: resultTime,
    total2: total2
    total3: total3
    total4: total4
};
}

detailsselected.update = function(arrayselected) {

var details = detailshow()
this._div.innerHTML =
'<b>Zipcodes</b><br>' + 
'Total time: <b>' + details.resultTime + ' hh:mm:ss</b><br>' +
'Total amount: <b>' + details.total + ' st</b><br>' +
'Region South amount: <b>' + details.total3 + ' st</b><br>' +
'Region North amount: <b>' + details.total4 + ' st</b><br>' +
'Distance: <b>' + details.total2.toFixed(1) + ' km</b><br>';
$('#suma', window.parent.document).val(details.resultTime, details.total, details.total2, details.total3, details.total4);


};

detailsselected.addTo(map);

我确实尝试了以下方法，但没有成功

    function filt_north (feature){
        if (feature.properties.REGION === 'REGION NORTH' )
        return true;
    }

    total4 += filt_north.(properties.amount), // amount for Region North only

---

您编写的

filt\u north

函数看起来不错，只需添加一个

filt\u south

过滤器即可获得南部区域并执行以下操作：

let filteredResults = featuresSelected.filter(
   result => filt_north(result.feature) || filt_south(result.feature)
);

for (let result of filteredResults) {
    var properties = result.feature.properties;
    ...

---

尝试了你的解决方案，似乎它破坏了代码，并且总数根本没有加起来=停止工作。我这样做了，是否应该用不同的方式？ 过滤功能：

    function filt_south (feature){
    if (feature.properties.REGION === 'REGION SOUTH')
    return true;
}

function filt_north (feature){
    if (feature.properties.REGION === 'REGION NORTH')
    return true;
}

然后换成这个（我一定是做错了什么）：

//现在获取选定多边形的总数
var detailshow=函数（）{
var结果=“”
var总计=0
var total1=0
var total2=0
var total3=0
var total4=0
让filteredResults=功能Selected.filter(
结果=>filt_south（result.feature）| filt_north（result.feature）
);
for（让筛选结果返回结果）{
变量属性=result.feature.properties；
对于（var i=0；i
Zipcode:${properties.Zipcode}
`；
合计+=properties.amount，//所有区域的合计金额
total1+=属性。平均_时间，
total2+=属性.distance，
total3+=filt_south（properties.amount），//仅南部地区的金额
total4+=filt_north（properties.amount）//仅适用于北部地区的金额
//将秒转换为时间格式
var convertTime=函数（输入，分隔符）{
var pad=函数（输入）{返回输入<10？“0”+输入：输入；}；
返回[
pad（数学楼层（输入/3600）），
pad（数学楼层（输入%3600/60）），
pad（数学楼层（输入%60）），
].join（分隔符的类型！=“未定义”？分隔符：“：”）；
}
var resultTime=转换时间（总计1）；
}
}
返回{
结果:结果,，
总计：总计，
结果时间：结果时间，
总计2：总计2
总计3：总计3
总计4：总计4
};
}
detailsselected.update=函数（arrayselected）{
var details=detailshow（）
这是.\u div.innerHTML=
“Zipcode
”+
'总时间：'+details.resultTime+'hh:mm:ss
'+
'总金额：'+details.Total+'st
'+
'地区南部金额：'+details.total3+'st
'+
'地区北部金额：'+details.total4+'st
'+
“距离：”+细节。总计2.固定距离（1）+“公里
”；
$（'#suma'，window.parent.document）.val（details.resultTime，details.total，details.total2，details.total3，details.total4）；
};
已选择详细信息。添加到（地图）

所选功能[0]看起来像什么？也添加了该部分，谢谢

let filteredResults = featuresSelected.filter(
   result => filt_north(result.feature) || filt_south(result.feature)
);

for (let result of filteredResults) {
    var properties = result.feature.properties;
    ...

    function filt_south (feature){
    if (feature.properties.REGION === 'REGION SOUTH')
    return true;
}

function filt_north (feature){
    if (feature.properties.REGION === 'REGION NORTH')
    return true;
}

    // Now get the totals of selected polygons
    var detailshow = function() {
    var result = ''
    var total = 0
    var total1 = 0
    var total2 = 0
    var total3 = 0
    var total4 = 0

    let filteredResults = featuresSelected.filter(
        result => filt_south(result.feature) || filt_north(result.feature)
        );

    for (let result of filteredResults) {
        var properties = result.feature.properties;

    for (var i = 0; i < featuresSelected.length; i++) { 
        var properties = featuresSelected[i].feature.properties
        result +=
        `
    ${properties.CITY}<br>
    Zipcode: ${properties.ZIPCODE}
    <a href="#" onclick=dellayer(${properties.ZIPCODE})>Delete</a>
    <hr>`;
    total += properties.amount, // sum amount for all regions
    total1 += properties.average_time,
    total2 += properties.distance,
    total3 += filt_south (properties.amount), // amount for Region South only
    total4 += filt_north (properties.amount) // amount for Region North only

    // Convert seconds to timeformat
    var convertTime = function (input, separator) {
    var pad = function(input) {return input < 10 ? "0" + input : input;};
        return [
        pad(Math.floor(input / 3600)),
        pad(Math.floor(input % 3600 / 60)),
        pad(Math.floor(input % 60)),
        ].join(typeof separator !== 'undefined' ?  separator : ':' );
    }

var resultTime = convertTime(total1);
}
}
return {
    result: result,
    total: total,
    resultTime: resultTime,
    total2: total2
    total3: total3
    total4: total4
};
}

detailsselected.update = function(arrayselected) {

var details = detailshow()
this._div.innerHTML =
'<b>Zipcodes</b><br>' + 
'Total time: <b>' + details.resultTime + ' hh:mm:ss</b><br>' +
'Total amount: <b>' + details.total + ' st</b><br>' +
'Region South amount: <b>' + details.total3 + ' st</b><br>' +
'Region North amount: <b>' + details.total4 + ' st</b><br>' +
'Distance: <b>' + details.total2.toFixed(1) + ' km</b><br>';
$('#suma', window.parent.document).val(details.resultTime, details.total, details.total2, details.total3, details.total4);


};

detailsselected.addTo(map)