Javascript 嵌套模式/子文档对象中的Mongoose findById()-聚合
我有一个对象Javascript 嵌套模式/子文档对象中的Mongoose findById()-聚合,javascript,mongodb,mongoose,mongodb-query,aggregation-framework,Javascript,Mongodb,Mongoose,Mongodb Query,Aggregation Framework,我有一个对象类型。它包含多个模式。我需要根据其id查找项目,但该项目可能位于exampleOne或exampleotwo中(注意:将使用两个以上的模式) 例如,在此服务器上查询“id:608a5b290e635ece6828141e”: { "_id": "608642db80a36336946620aa", "title": "titleHere", "types": { &
类型
。它包含多个模式。我需要根据其id查找项目,但该项目可能位于exampleOne
或exampleotwo
中(注意:将使用两个以上的模式)
例如,在此服务器上查询“id:608a5b290e635ece6828141e”
:
{
"_id": "608642db80a36336946620aa",
"title": "titleHere",
"types": {
"exampleOne": [
{
"_id": "6086430080a36336946620ab",
"front": "front",
"back": "back"
},
{
"_id": "608a5b186ee1598ac9c222b4",
"front": "front2",
"back": "back2"
}
],
"exampleTwo": [
{
"_id": "608a5b290e635ece6828141e", // the queried document
"normal": {
"front": "2front",
"back": "2back"
},
"reversed": {
"front": "2frontReversed",
"back": "2backReversed"
}
},
{
"_id": "608a5b31a3f9806de2537269",
"normal": {
"front": "2front2",
"back": "2back2"
},
"reversed": {
"front": "2frontReversed2",
"back": "2backReversed2"
}
}
]
}
}
应返回:
{
"_id": "608a5b290e635ece6828141e",
"normal": {
"front": "2front",
"back": "2back"
},
"reversed": {
"front": "2frontReversed",
"back": "2backReversed"
}
},
理想情况下,解决方案只需要一次搜索。我对此做了一些研究,但不知道如何搜索类型
中的所有对象,而不为每个模式创建搜索并查看其中是否有返回结果
以下是我的模式(如果需要):
var MainSchema = new Schema ({
title: { type: String, required: true, maxlength: 255 },
types: {
exampleOne: [exampleOneSchema],
exampleTwo: [exampleTwoSchema],
}
});
感谢您的帮助
谢谢
酸牙
演示-
我相信
$or
里面的$match
是不必要的-酸牙是的,我的坏牙
var exampleOneSchema = new Schema({
front: {type: String, required: true},
back: {type: String, required: true},
});
var exampleTwoSchema= new Schema({
normal: {
front: {type: String, required: true},
back: {type: String, required: true},
},
reversed: {
front: {type: String, required: true},
back: {type: String, required: true},
},
});
db.collection.aggregate([
{
$match: { // filter the document so uniwnd and group have only 1 record to deal with
$or: [
{ "types.exampleOne._id": "608a5b290e635ece6828141e" },
{ "types.exampleTwo._id": "608a5b290e635ece6828141e" }
]
}
},
{
$group: {
_id: "$_id",
docs: { $first: { "$concatArrays": [ "$types.exampleOne", "$types.exampleTwo" ] } } // join both array into 1 element
}
},
{ $unwind: "$docs" }, // break into individual documents
{
$match: { // filter the records
"docs._id": "608a5b290e635ece6828141e"
}
},
{ $replaceRoot: { "newRoot": "$docs" } } // set it to root
])