Javascript 如何检查两个数组是否包含相同的值，即使它们位于不同的索引中？

我正在做一个个人项目，最后一部分我是stump。我试图只获取与我数据库中的公司同名的公司的数据

最后，我的目标是将从以下两个调用中获得的两个JSON合并为一个

    Call one: $http.get('//localhost:8081/api/jobs').then(function(res) 
    Call two: localhost:8081/api/glassdoor/

完整代码：

    $http.get('//localhost:8081/api/jobs').then(function(res) {
    $scope.data = res.data; //data from the database
    $scope.size = $scope.data.length; //length 132
    for (var i = 0; i < $scope.size; i++) {
        if ($scope.data[i].glassdoor !== null && $scope.data[i].glassdoor !== undefined) {
            $scope.hasGlassdoor = [];
            for (var i = 0; i < $scope.size; i++) {
                if ($scope.data[i].glassdoor !== null && $scope.data[i].glassdoor !== undefined)
                    $scope.hasGlassdoor.push($scope.data[i]);
            }

            //Get the companies name that have glassdoor
            $scope.company = [];
            for (var j = 0; j < $scope.hasGlassdoor.length; j++) {
                $scope.company.push($scope.hasGlassdoor[j].company);
            }

            //Create the URL calls for my glassdoor api
            $scope.url = [];
            for (var x = 0; x < $scope.company.length; x++) {
                $scope.url.push('//localhost:8081/api/glassdoor/' + $scope.company[x]);
            }
            //For example : '//localhost:8081/api/glassdoor/A9.com'

            //Get the Glassdoor data
            var company = $scope.company;
            for (var j = 0; j < $scope.url.length; j++) {
                $http.get($scope.url[j]).then(function(response) {
                    $scope.gData = response.data;
                    $scope.gSize = $scope.gData.length;
                    $scope.gName = [];

                    //Get the names of the companies that glassdoor returns
                    for(var x = 0; x < $scope.gSize; x++){
                         if ($scope.gData[x] !== null && $scope.gData[x] !== undefined) {
                            if ($scope.gData[x].name !== null && $scope.gData[x].name !== undefined) {
                                    $scope.gName.push($scope.gData[x].name);
                            }
                         }
                    }
                    //Now I'm trying to only get the names of the companies that are in my variable company
                    //For example '//localhost:8081/api/glassdoor/6sense
                    //returns data for 6sense, and a company named 6sense Technologies
                    //I'm trying to just get the data of 6sense

                    //
                    //      TODO
                    //


                    // My try using loDash returns undefined.
                    // I'm trying to see if $scope.gName is in var Company.
                    //if(_.includes(company, $scope.gName)){
                    //    gd.push($scope.gName);
                    //}

                }); //this is what is calling the glassdoor api
            }//end of the for loop for url.
        } //if statement to check for null
    } //first for loop
}).catch(function(error, res) {
    console.log("Error:", error, res);
});

处理glassdoor调用的Server.js：

//Glassdoor api call
app.get('/api/glassdoor/:company', function(req, res, next) {
    var company = req.params.company;
    requestify.get('https://api.glassdoor.com/api/api.htm?t.p=PRODUCT&t.k=KEY&userip=0.0.0.0&useragent=&format=json&v=1&action=employers&q=' + company).then(function(response) {
        // Get the response body (JSON parsed or jQuery object for XMLs)
        gData = response.getBody();
        gData = gData.response.employers;
        res.json(gData);
    });



});

---

对数组排序，然后枚举它。如果previous===current，则有一个重复。

对数组排序，然后枚举它。如果previous===current，您就有一个重复。

这就是我解决它的方法

app.get('/api/glassdoor/:company', function(req, res, next) {
    var company = req.params.company;
    requestify.get('https://api.glassdoor.com/api/api.htm?t.p=PRODUCT&t.k=KEY&userip=0.0.0.0&useragent=&format=json&v=1&action=employers&q=' + company).then(function(response) {
        // Get the response body (JSON parsed or jQuery object for XMLs)
        gData = response.getBody();
        gData = gData.response.employers;
        //What I added to only send the data of the companies that where like 'company'
        for (var i = 0; i < gData.length; i++) {
            if (gData[i].name === company) {
                gData = gData[i];
                res.send(gData);
            }
        }
    });
});

app.get（'/api/glassdoor/：company'，函数（req，res，next）{
var公司=所需参数公司；
requestify.get（'https://api.glassdoor.com/api/api.htm?t.p=PRODUCT&t.k=KEY&userip=0.0.0.0&useragent=&format=json&v=1&action=employers&q=“+公司）。然后（功能（响应）{
//获取响应主体（JSON解析或XMLs的jQuery对象）
gData=response.getBody（）；
gData=gData.response.employers；
//我添加的内容仅发送喜欢“公司”的公司的数据
对于（变量i=0；i

---

这并不能回答整个问题，但这就是我如何解决我的特殊问题。

这就是我如何解决的

app.get('/api/glassdoor/:company', function(req, res, next) {
    var company = req.params.company;
    requestify.get('https://api.glassdoor.com/api/api.htm?t.p=PRODUCT&t.k=KEY&userip=0.0.0.0&useragent=&format=json&v=1&action=employers&q=' + company).then(function(response) {
        // Get the response body (JSON parsed or jQuery object for XMLs)
        gData = response.getBody();
        gData = gData.response.employers;
        //What I added to only send the data of the companies that where like 'company'
        for (var i = 0; i < gData.length; i++) {
            if (gData[i].name === company) {
                gData = gData[i];
                res.send(gData);
            }
        }
    });
});

app.get（'/api/glassdoor/：company'，函数（req，res，next）{
var公司=所需参数公司；
requestify.get（'https://api.glassdoor.com/api/api.htm?t.p=PRODUCT&t.k=KEY&userip=0.0.0.0&useragent=&format=json&v=1&action=employers&q=“+公司）。然后（功能（响应）{
//获取响应主体（JSON解析或XMLs的jQuery对象）
gData=response.getBody（）；
gData=gData.response.employers；
//我添加的内容仅发送喜欢“公司”的公司的数据
对于（变量i=0；i

这并不能回答整个问题，但我就是这样解决我的问题的