Javascript 如何减少多个请求导致的加载时间
我正在开发一个新闻聚合器网站,在其中添加了24个发布者,所有发布者的数据都以xml文件的形式存在,所以我使用ajax调用它们。但加载页面需要30秒。我的网页中有四个部分(为你、技术、政治、电影/电视),每个部分都有一个外部JS文件。这些文件正在请求数据。PLZ帮助我减少页面加载时间,并建议一些策略Javascript 如何减少多个请求导致的加载时间,javascript,jquery,ajax,performance,load,Javascript,Jquery,Ajax,Performance,Load,我正在开发一个新闻聚合器网站,在其中添加了24个发布者,所有发布者的数据都以xml文件的形式存在,所以我使用ajax调用它们。但加载页面需要30秒。我的网页中有四个部分(为你、技术、政治、电影/电视),每个部分都有一个外部JS文件。这些文件正在请求数据。PLZ帮助我减少页面加载时间,并建议一些策略 //technology JS file code sample $.when($.get('https://cors-anywhere.herokuapp.com/https://feed.
//technology JS file code sample
$.when($.get('https://cors-anywhere.herokuapp.com/https://feed.cnet.com/feed/topics/sci-tech'), $.get('https://cors-anywhere.herokuapp.com/https://in.mashable.com/tech.xml')).then(function(r1, r2) {
// console.log(r1[0]);
// console.log(r2[0]);
// cnet article
$(r1[0]).find('item').each(function(i, j) {
title = $(j).find('title').text();
description = $(j).find('description').text();
link = $(j).find('link').text();
thumbnail = $(j).find('[url]').attr('url');
newsname = "Cnet";
logo = "http://i.i.cbsi.com/cnwk.1d/i/ne/gr/prtnr/CNET_Logo_150.gif";
articlestech(i, title, description, link, thumbnail, newsname, logo);
});
//Mashable articles
$(r2[0]).find('item').each(function(i, j) {
title = $(j).find('title').text();
description = $(j).find('description').text();
//pos3 = description.indexOf("</a>");
// des = description.substring(pos3 + 2);
// thumbnail = $(j).find('image').text();
link = $(j).find('link').text();
var pos2 = description.indexOf("width");
var pos1 = description.indexOf("src=");
thumbnail = description.substring(pos1 + 5, pos2 - 2);
newsname = "Mashable India Tech";
logo = "https://media.glassdoor.com/sqll/255718/mashable-squarelogo-1430326903133.png";
des = "";
articlestech(i, title, des, link, thumbnail, newsname, logo);
});}) ;
//movies/tv shows code sample
$.ajax({
type: "GET",
url: "https://cors-anywhere.herokuapp.com/https://www.cinemablend.com/rss/topic/reviews/movies",
dataType: "xml",
success: function(xml) {
$(r1[0]).find('item').each(function(i, j) {
title = $(j).find('title').text();
description = $(j).find('description').text() + "...";
link = $(j).find('link').text();
//console.log(link);
thumbnail = $(j).find('enclosure').attr('url');
//console.log(thumbnail);
newsname = "Cinemablend";
logo = "https://s3.amazonaws.com/media.muckrack.com/groups/icons/cinemablend.jpeg";
articlestech(i, title, description, link, thumbnail, newsname, logo);
});
}
});
$.ajax({
type: "GET",
url: "https://cors-anywhere.herokuapp.com/https://www.cinejosh.com/rss-feed/1/review.html",
dataType: "xml",
success: function(xml) {
$(xml).find('item').each(function(i, j) {
title = $(j).find('title').text();
//des = $(j).find('description').text();
link = $(j).find('link').text();
description = "";
thumbnail = $(j).find('[url]').attr('url');;
console.log(thumbnail);
newsname = "CineJosh";
logo = "https://www.cinejosh.com/gallereys/others/normal/cinejosh_logo_1902160805/cinejosh_logo_1902160805_01.jpg";
articlestech(i, title, description, link, thumbnail, newsname, logo);
});
}
});
//技术JS文件代码示例
$.when($.get('https://cors-anywhere.herokuapp.com/https://feed.cnet.com/feed/topics/sci-tech'),$.get('https://cors-anywhere.herokuapp.com/https://in.mashable.com/tech.xml)。然后(函数(r1,r2){
//console.log(r1[0]);
//console.log(r2[0]);
//cnet文章
$(r1[0])。查找('item')。每个(函数(i,j){
title=$(j).find('title').text();
description=$(j).find('description').text();
link=$(j).find('link').text();
缩略图=$(j).find('[url]').attr('url');
newsname=“Cnet”;
徽标=”http://i.i.cbsi.com/cnwk.1d/i/ne/gr/prtnr/CNET_Logo_150.gif";
articlestech(i、标题、描述、链接、缩略图、新闻名称、徽标);
});
//可捣碎物品
$(r2[0])。查找('item')。每个(函数(i,j){
title=$(j).find('title').text();
description=$(j).find('description').text();
//pos3=description.indexOf(“”);
//des=描述子串(pos3+2);
//缩略图=$(j).find('image').text();
link=$(j).find('link').text();
var pos2=描述。索引(“宽度”);
var pos1=description.indexOf(“src=”);
缩略图=description.substring(位置1+5,位置2-2);
newsname=“Mashable India Tech”;
徽标=”https://media.glassdoor.com/sqll/255718/mashable-squarelogo-1430326903133.png";
des=“”;
articlestech(i、标题、des、链接、缩略图、新闻名称、徽标);
});}) ;
//电影/电视节目代码示例
$.ajax({
键入:“获取”,
url:“https://cors-anywhere.herokuapp.com/https://www.cinemablend.com/rss/topic/reviews/movies",
数据类型:“xml”,
成功:函数(xml){
$(r1[0])。查找('item')。每个(函数(i,j){
title=$(j).find('title').text();
description=$(j).find('description').text()+“…”;
link=$(j).find('link').text();
//控制台日志(链接);
缩略图=$(j).find('enclosure').attr('url');
//控制台日志(缩略图);
newsname=“Cinemablend”;
徽标=”https://s3.amazonaws.com/media.muckrack.com/groups/icons/cinemablend.jpeg";
articlestech(i、标题、描述、链接、缩略图、新闻名称、徽标);
});
}
});
$.ajax({
键入:“获取”,
url:“https://cors-anywhere.herokuapp.com/https://www.cinejosh.com/rss-feed/1/review.html“,
数据类型:“xml”,
成功:函数(xml){
$(xml).find('item')。每个(函数(i,j){
title=$(j).find('title').text();
//des=$(j).find('description').text();
link=$(j).find('link').text();
description=“”;
缩略图=$(j).find('[url]').attr('url');;
控制台日志(缩略图);
newsname=“CineJosh”;
徽标=”https://www.cinejosh.com/gallereys/others/normal/cinejosh_logo_1902160805/cinejosh_logo_1902160805_01.jpg";
articlestech(i、标题、描述、链接、缩略图、新闻名称、徽标);
});
}
});
Rest两个JS文件具有相同的代码结构。如何减少加载时间。问题在于,您正在等待所有六个请求返回,以开始处理响应。正如我从您提供的代码片段中看到的,请求之间并不相互依赖,因此您可以单独执行所有请求,当第一个请求完成时,用户将能够在屏幕上看到结果 那么这个,
$.when(
$.get('https://cors-anywhere.herokuapp.com/https://feed.cnet.com/feed/topics/sci-tech'),
$.get('https://cors-anywhere.herokuapp.com/https://in.mashable.com/tech.xml'),
$.get('https://www.theverge.com/rss/tech/index.xml'),
$.get('https://cors-anywhere.herokuapp.com/https://www.buzzfeed.com/tech.xml'),
$.get('https://cors-anywhere.herokuapp.com/https://www.cnbc.com/id/19854910/device/rss/rss.html'),
$.get('https://cors-anywhere.herokuapp.com/https://www.engadget.com/rss.xml'))
必须是这样的:
$.when($.get('https://cors-anywhere.herokuapp.com/https://feed.cnet.com/feed/topics/sci-tech')).then(function(r1) {
$(r1[0]).find('item').each(function(i, j) {
title = $(j).find('title').text();
description = $(j).find('description').text();
link = $(j).find('link').text();
thumbnail = $(j).find('[url]').attr('url');
newsname = "Cnet";
logo = "http://i.i.cbsi.com/cnwk.1d/i/ne/gr/prtnr/CNET_Logo_150.gif";
articlestech(i, title, description, link, thumbnail, newsname, logo);
});
})
$.when($.get('https://cors-anywhere.herokuapp.com/https://in.mashable.com/tech.xml')).then(function(r1) {
$(r2[0]).find('item').each(function(i, j) {
title = $(j).find('title').text();
description = $(j).find('description').text();
//pos3 = description.indexOf("</a>");
// des = description.substring(pos3 + 2);
// thumbnail = $(j).find('image').text();
link = $(j).find('link').text();
var pos2 = description.indexOf("width");
var pos1 = description.indexOf("src=");
thumbnail = description.substring(pos1 + 5, pos2 - 2);
newsname = "Mashable India Tech";
logo = "https://media.glassdoor.com/sqll/255718/mashable-squarelogo-1430326903133.png";
des = "";
articlestech(i, title, des, link, thumbnail, newsname, logo);
});
})
$.when($.get()https://cors-anywhere.herokuapp.com/https://feed.cnet.com/feed/topics/sci-然后(功能(r1){
$(r1[0])。查找('item')。每个(函数(i,j){
title=$(j).find('title').text();
description=$(j).find('description').text();
link=$(j).find('link').text();
缩略图=$(j).find('[url]').attr('url');
newsname=“Cnet”;
徽标=”http://i.i.cbsi.com/cnwk.1d/i/ne/gr/prtnr/CNET_Logo_150.gif";
articlestech(i、标题、描述、链接、缩略图、新闻名称、徽标);
});
})
$.when($.get('https://cors-anywhere.herokuapp.com/https://in.mashable.com/tech.xml)。然后(函数(r1){
$(r2[0])。查找('item')。每个(函数(i,j){
title=$(j).find('title').text();
description=$(j).find('description').text();
//pos3=description.indexOf(“”);
//des=描述子串(pos3+2);
//缩略图=$(j).find('image').text();
link=$(j).find('link').text();
var pos2=描述。索引(“宽度”);
var pos1=description.indexOf(“src=”);
缩略图=description.substring(位置1+5,位置2-2);
newsname=“Mashable India Tech”;
徽标=”https://media.glassdoor.com/sqll/255718/mashable-squarelogo-1430326903133.png";
des=“”;
articlestech(i、标题、des、链接、缩略图、新闻名称、徽标);
});
})
…请求是否相互依赖?它们是我请求的独立url,其顺序意味着只有在从一个url请求整个数据后,另一个ajax请求才开始确定,我将签出HI,I d