Javascript 如何使用非-1的答案记录数组中正确元素的索引
我最多只能从各种方法中得到“-1”,如.indexOf、.findIndex、returning、console.logging。 有一个名为fifaData.js的单独数组文件,我可以检索一些信息,但不能检索索引。我猜这是一个语法错误,但我已经做了好几天了,还没弄明白。这是我的第一个问题,如果我很糟糕,我很抱歉。我发现的其他答案都是“-1”。这绝对不是我想要的回报Javascript 如何使用非-1的答案记录数组中正确元素的索引,javascript,arrays,indexing,Javascript,Arrays,Indexing,我最多只能从各种方法中得到“-1”,如.indexOf、.findIndex、returning、console.logging。 有一个名为fifaData.js的单独数组文件,我可以检索一些信息,但不能检索索引。我猜这是一个语法错误,但我已经做了好几天了,还没弄明白。这是我的第一个问题,如果我很糟糕,我很抱歉。我发现的其他答案都是“-1”。这绝对不是我想要的回报 const popupQuery=prompt("Enter the Year , Data sought",
const popupQuery=prompt("Enter the Year , Data sought","1930,Home Team Name"), targetYear=popupQuery.split(",")[0],targetData=popupQuery.split(",")[1];
function fifaParse(targetYear){
for(let i=0; i<fifaData.length; i++) {
if (fifaData[i].year === targetYear && fifaData[i].Stage == "Group 4") {
console.log('i: ', i);}}}
fifaParse(targetYear)```
Example (fifa.js) :
```export const fifaData = [
{
"Year": 1930,
"Datetime": "13 Jul 1930 - 15:00",
"Stage": "Group 1",
"Stadium": "Pocitos",
"City": "Montevideo",
"Home Team Name": "France",
"Home Team Goals": 4,
"Away Team Goals": 1,
"Away Team Name": "Mexico",
"Win conditions": "",
"Attendance": 4444,
"Half-time Home Goals": 3,
"Half-time Away Goals": 0,
"Referee": "LOMBARDI Domingo (URU)",
"Assistant 1": "CRISTOPHE Henry (BEL)",
"Assistant 2": "REGO Gilberto (BRA)",
"RoundID": 201,
"MatchID": 1096,
"Home Team Initials": "FRA",
"Away Team Initials": "MEX"
},
{
"Year": 1930,
"Datetime": "13 Jul 1930 - 15:00",
"Stage": "Group 4",
"Stadium": "Parque Central",
"City": "Montevideo",
"Home Team Name": "USA",
"Home Team Goals": 3,
"Away Team Goals": 0,
"Away Team Name": "Belgium",
"Win conditions": "",
"Attendance": 18346,
"Half-time Home Goals": 2,
"Half-time Away Goals": 0,
"Referee": "MACIAS Jose (ARG)",
"Assistant 1": "MATEUCCI Francisco (URU)",
"Assistant 2": "WARNKEN Alberto (CHI)",
"RoundID": 201,
"MatchID": 1090,
"Home Team Initials": "USA",
"Away Team Initials": "BEL"
}]```
const-popupQuery=prompt(“输入年份,寻找的数据”,“1930,主队名称”),targetYear=popupQuery.split(“,”[0],targetData=popupQuery.split(“,”[1];
功能五区(目标耳){
for(设i=0;i对我来说似乎是一个数据类型问题
检查targetyear和fifaData[i]的类型。年份
对于不考虑数据类型的匹配,您可以修改检查以使用=而不是==
if (fifaData[i].year == targetYear)
如果不共享至少一个与fifaData.js
结构匹配的JSON
示例,没有人能够帮助您。请提供变量“fifaData”数据结构信息,它将帮助我们更好地理解问题。你在很大程度上是正确的。我现在知道我没有大写。Year。还有==建议很有帮助。事实证明“-1”表示从未满足过条件。如果我知道我会更敏锐。;)非常感谢!