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javascript-检查数组是否为空?_Javascript_Regex - Fatal编程技术网

javascript-检查数组是否为空?

javascript-检查数组是否为空?,javascript,regex,Javascript,Regex,我试图检查var匹配是否为空,但我没有任何运气。任何帮助都将不胜感激 var url = document.getElementById("defineNewURL").value; var urlReg; var subject = url.toString(); var regex = /^((http[s]?|ftp):\/)?\/?([^:\/\s]+)((\/\w+)*\/)([\w\-\.]+[^#?\s]+)(.*)?(#[\w\-]+)?$/ match = regex.ex

我试图检查var匹配是否为空,但我没有任何运气。任何帮助都将不胜感激

var url = document.getElementById("defineNewURL").value;
var urlReg;


var subject = url.toString();
var regex = /^((http[s]?|ftp):\/)?\/?([^:\/\s]+)((\/\w+)*\/)([\w\-\.]+[^#?\s]+)(.*)?(#[\w\-]+)?$/
match = regex.exec(subject);

if(typeof match == 'undefined'){
    urlReg = url;
}else{
    urlReg = match[6];
}

/.exec
在不匹配时返回
null
, 和一个匹配的对象。 由于所有对象都是真实的,
null
是虚假的, 您可以这样写条件:

if (match) {
    urlReg = match[6];
} else {
    urlReg = url;
}
var url = document.getElementById("defineNewURL").value;
var urlReg;


var subject = url.toString();
var regex = /^((http[s]?|ftp):\/)?\/?([^:\/\s]+)((\/\w+)*\/)([\w\-\.]+[^#?\s]+)(.*)?(#[\w\-]+)?$/
match = regex.exec(subject);

if(match == null){
    urlReg = url;
}else{
    urlReg = match[6];
}

regex.exec
不返回undefined,但返回null。在您的代码中:

typeof match
返回
对象

看看:

并尝试使您的代码如下所示:

if (match) {
    urlReg = match[6];
} else {
    urlReg = url;
}
var url = document.getElementById("defineNewURL").value;
var urlReg;


var subject = url.toString();
var regex = /^((http[s]?|ftp):\/)?\/?([^:\/\s]+)((\/\w+)*\/)([\w\-\.]+[^#?\s]+)(.*)?(#[\w\-]+)?$/
match = regex.exec(subject);

if(match == null){
    urlReg = url;
}else{
    urlReg = match[6];
}

请添加数组。