Javascript 表达式模式匹配

我有一个类似的问题，除了Javascript而不是C

基本上，我希望能够对表达式进行模式匹配，而不是使用一长串

if

语句，如下所示：

var person.annoyingAction = match([person.gender, person.ageGroup],
      [male, child], breakingStuff,
      [male, teenager], drivingRecklessly,
      [male, adult], beingLazyAfterComingHomeFromWork
      [female, child], screechingInAnUnbelievablyHighPitchedVoice,
      [female, teenager], knowingEverything,
      [female, adult], askingPeopleIfTheyThinkIAmTooFat
      [_, baby], cryingEveryTwoHoursAtNight,
      [_,_], beingHuman);

---

有人知道如何在Javascript中实现类似的功能吗？

我不知道现有的干净解决方案，但这里有一个与您的示例相匹配的简单实现：

var match = function(target) {
  for (i = 1; i < arguments.length; i += 2) {
    if (target[0] == arguments[i][0] && target[1] == arguments[i][1]) {
      return arguments[i + 1];
    }
  }
}

在JavaScript中，您无法直接比较数组（

[1,2]！=[1,2]

），因此需要单独比较元素

var result = match(["Yellow", "Food"],
  ["Red", "Food"], "Apple",
  ["Green", "Plant"], "Grass",
  ["Yellow", "Thing"], "Schoolbus",
  ["Yellow", "Food"], "Banana",
  ["Yellow", "Foot"], "Bad"
)

alert(result) # displays "Banana"