Javascript 计算字符串中的唯一单词
下面我尝试为一个函数提供字符串数组,该函数将唯一的字添加到字数组中,如果该字已经在数组中,则增加计数数组中相应元素的计数:Javascript 计算字符串中的唯一单词,javascript,arrays,Javascript,Arrays,下面我尝试为一个函数提供字符串数组,该函数将唯一的字添加到字数组中,如果该字已经在数组中,则增加计数数组中相应元素的计数: var words = []; var counts = []; calculate([a, b]); calculate([a, c]); function calculate(result) { for (var i = 0; i < result.length; i++) { var check = 0; for (v
var words = [];
var counts = [];
calculate([a, b]);
calculate([a, c]);
function calculate(result) {
for (var i = 0; i < result.length; i++) {
var check = 0;
for (var j = 0; i < tags.length; i++) {
if (result[i] == tags[j]) {
check = 1;
counts[i] = counts[i] + 20;
}
}
if (check == 0) {
tags.push(result[i]);
counts.push(20);
}
check = 0;
}
}
var-words=[];
var计数=[];
计算([a,b]);
计算([a,c]);
函数计算(结果){
对于(变量i=0;i
但是,输出结果如下所示:
单词=a,b
计数=2,1
当我期望它是:
单词=a、b、c
计数=2,1,1
提前感谢您的帮助有几件事出错了,下面是工作代码:
var words = [];
var counts = [];
calculate(["a", "b"]);
calculate(["a", "c"]);
function calculate(result) {
for (var i = 0; i < result.length; i++) {
var check = 0;
for (var j = 0; j < words.length; j++) {
if (result[i] == words[j]) {
check = 1;
++counts[j];
}
}
if (check == 0) {
words.push(result[i]);
counts.push(1);
}
check = 0;
}
}
结果:
>> seen
[object Object] {
a: 2,
b: 1,
c: 1
}
JSBin:将问题分解为具有良好名称的方法有助于您制定逻辑 试试这个:
<script type="text/javascript">
var words = [];
var counts = [];
calculate(["a", "b"]);
calculate(["a", "c"]);
console.log(words);
console.log(counts);
function calculate(result) {
for (var i=0; i<result.length; i++) {
if (array_contains(words, result[i])) {
counts[result[i]]++;
} else {
words.push(result[i]);
counts[result[i]] = 1;
}
}
}
function array_contains(array, value) {
for (var i=0; i<array.length; i++)
if (array[i] == value)
return true;
return false;
}
</script>
var-words=[];
var计数=[];
计算([“a”,“b”]);
计算([“a”,“c”]);
控制台日志(文字);
控制台日志(计数);
函数计算(结果){
对于(var i=0;i请检查:
您可以在以下设备上进行测试:
以下是我的解决方案(使用对象):
你声明了一个words
数组,但从未使用过它。你使用了一个tags
数组,但从未声明过。我假设它们是同一个数组?你的第二个for循环错误。你应该迭代j
j=0;j
<script type="text/javascript">
var words = [];
var counts = [];
calculate(["a", "b"]);
calculate(["a", "c"]);
console.log(words);
console.log(counts);
function calculate(result) {
for (var i=0; i<result.length; i++) {
if (array_contains(words, result[i])) {
counts[result[i]]++;
} else {
words.push(result[i]);
counts[result[i]] = 1;
}
}
}
function array_contains(array, value) {
for (var i=0; i<array.length; i++)
if (array[i] == value)
return true;
return false;
}
</script>
var words = [];
var counts = [];
calculate(['a', 'b']);
calculate(['a', 'c']);
calculate(['a', 'b', 'c']);
function calculate(inputs) {
for (var i = 0; i < inputs.length; i++) {
var isExist = false;
for (var j = 0; j < words.length; j++) {
if (inputs[i] == words[j]) {
isExist = true
counts[i] = counts[i] + 1;
}
}
if (!isExist) {
words.push(inputs[i]);
counts.push(1);
}
isExist = false;
}
}
console.log(words);
console.log(counts);
["a", "b", "c"] (index):46
[3, 2, 2]
const checkWord = (str) => {
let collection = {};
// split the string into an array
let words = str.split(' ');
words.forEach((word) => {
collection[word] = word;
});
// loop again to check against the array and assign a count
for (let j = 0; j < words.length; j++) {
if (words[j] === collection[words[j]]) {
collection[words[j]] = 0;
}
collection[words[j]]++
}
console.log(collection);
};
const checkWord = (str) => {
let collection = {};
let words = str.split(' ');
words.forEach((word) => {
collection[word] = word;
});
for (var i = 0; i < words.length; i++) {
if (words[i] === collection[words[i]]) {
collection[words[i]] = 0;
}
}
let total = words.reduce((occurrences, word) => {
collection[word]++
return collection;
}, 0);
console.log(total);
};