Javascript 我检测不出这个错误。为什么第三和第四（否则如果）不起作用

我无法检测到我在下面犯的错误。为什么第三和第四（否则如果）不起作用。你能检测出错误吗

       var x = prompt ("Hey , Who are you ? Put Your name below ");
        if (x === "najmul"){
            alert ("Hey, Young Man. How was the journey?");
        }

        else if (x === "mahmud" || "mona"){
            alert ("hum, I saw you with Najmul!");
        }

        else if (x === "sabbir"){
            alert ("Further options are not enabled for under 18");
        }

        else if (x === "Abbas"){
            alert ("Hola Abbas");
        }
        else {
            alert ("Do I know You?");

        }

替换

else if (x === "mahmud" || "mona"){

与

因此，

if（x==“mahmud”| |“mona”）

总是

真的

如果（x==“mahmud”| | x==“mona”）

出现以下情况，请尝试

：

x === "mahmud" || "mona"

将始终是：
x==“mahmud”
，因为它是如何解析的

使用：

因此，它的计算结果总是
true
您的第二个条件总是true。这是正确的代码：

   var x = prompt ("Hey , Who are you ? Put Your name below ");
    if (x === "najmul"){
        alert ("Hey, Young Man. How was the journey?");
    }

    else if (x === "mahmud" || x === "mona"){
        alert ("hum, I saw you with Najmul!");
    }

    else if (x === "sabbir"){
        alert ("Further options are not enabled for under 18");
    }

    else if (x === "Abbas"){
        alert ("Hola Abbas");
    }
    else {
        alert ("Do I know You?");

    }

如果要将一个值与两个值进行比较，必须单独进行检查，如

x == "mahmud" || x == "mona"

将
else if（x==“mahmud”| |“mona”）{
替换为
else if（x==“mahmud”| | x==“mona”）{
如果你想要一个短条件，它可以是
else if（[“mahmud”，“mona”）。indexOf（x）+1）
不，想法。这与上面给出的答案完全相同。与@vaxo相同，是的，因为这是解决方案。与评论相同，是的，是同一个人。不明白为什么这两个答案立即被否决。奇怪。
   var x = prompt ("Hey , Who are you ? Put Your name below ");
    if (x === "najmul"){
        alert ("Hey, Young Man. How was the journey?");
    }

    else if (x === "mahmud" || x === "mona"){
        alert ("hum, I saw you with Najmul!");
    }

    else if (x === "sabbir"){
        alert ("Further options are not enabled for under 18");
    }

    else if (x === "Abbas"){
        alert ("Hola Abbas");
    }
    else {
        alert ("Do I know You?");

    }

x == "mahmud" || x == "mona"