显示自己会话的影院座位布局（PHP和Javascript）

这是我的桌子

CREATE TABLE `seat` (
  `Seat_ID` int(11) NOT NULL,
  `Hall_No` int(11) NOT NULL,
  `Seat_No` varchar(255) NOT NULL,
  `Seat_Price` int(11) NOT NULL,
  `Seat_Status` text NOT NULL
)

CREATE TABLE `hall` (
  `Hall_No` int(11) NOT NULL,
  `Cinema_ID` int(11) NOT NULL,
  `Hall_Size` varchar(20) NOT NULL,
  `Num_Seats` int(11) NOT NULL
) 

CREATE TABLE `reservation_seat` (
  `ResevationSeat_ID` int(11) NOT NULL,
  `Seat_ID` int(11) NOT NULL,
  `Reservation_ID` int(11) NOT NULL
) 

CREATE TABLE `ticket_reservation` (
  `Reservation_ID` int(11) NOT NULL,
  `Member_ID` int(11) NOT NULL,
  `Session_ID` int(11) NOT NULL,
  `Reservation_Date` varchar(255) NOT NULL
)

CREATE TABLE `session` (
  `Session_ID` int(11) NOT NULL,
  `Movie_ID` int(11) NOT NULL,
  `Hall_No` int(11) NOT NULL,
  `Showing_Date` date NOT NULL,
  `Start_Time` time NOT NULL,
  `End_Time` time NOT NULL,
  `Session_Status` varchar(15) NOT NULL
) 

这里的代码是如何显示从A行到C行的座椅

<tr class="a-row">
            <?php 
                $mysql = 
                "SELECT * FROM seat, session, hall 
                WHERE Seat_No LIKE 'A_%' 
                AND seat.Hall_No = hall.Hall_No 
                AND session.Session_ID = $sesid 
                AND session.Hall_No = hall.Hall_No ";

                $result = mysqli_query($connect,$mysql);
                while($row = mysqli_fetch_assoc($result))
                {       
            ?>
                    <td></t><input type="checkbox" name="seat[]" value="<?php echo $row['Seat_ID']?>" id="<?php echo $row['Seat_No']?>"><label id="available" for="<?php echo $row['Seat_No']?>"><?php echo $row["Seat_No"]?></label></td>

            <?php   
                }
            ?>  
            </tr>

---

这些是我编码的行，用于检查它是否显示了他们自己会议中正确的预订座位。

Stop。永远不要使用隐式（逗号）连接。解决这个问题。请参阅：，然后返回给我们。这看起来像MySQL，而不是SQL Server。你为什么把两者都贴上标签？

$checkreserve = 
"SELECT * from 
ticket_reservation as tr, 
reservation_seat as rs 
WHERE tr.Session_ID = $sesid 
AND tr.Reservation_ID = rs.Reservation_ID";