Jpa 通过spring规范创建where子句
我试图通过使用Spring规范在where子句中创建一个复杂的条件。因此,我尝试构建本机sql:Jpa 通过spring规范创建where子句,jpa,spring-data-jpa,spring-data,Jpa,Spring Data Jpa,Spring Data,我试图通过使用Spring规范在where子句中创建一个复杂的条件。因此,我尝试构建本机sql: SELECT * FROM Student WHERE grade > 10 AND age is null OR ( ( gender = 1 and age > 20 ) or (gender !=1 and age > 18) ) 但在构建的查询结束时,忽略了最外面的括号,因此结果是: SELECT * FROM Student WHERE grade
SELECT * FROM Student
WHERE grade > 10
AND age is null
OR (
( gender = 1 and age > 20 ) or (gender !=1 and age > 18)
)
但在构建的查询结束时,忽略了最外面的括号,因此结果是:
SELECT * FROM Student
WHERE grade > 10
AND ( age is null
OR gender = 1
and age > 20
OR gender !=1
and age > 18 )
)
这就是我如何组合规格:
Specification<Student> spec = new GradeSpec()
.and(new AgeNotNullSpec())
.or(new Gender1Spec().or(new Gender2Spec()))
Specification spec=新等级spec()
.和(新的AgentNullSpec())
.或(新性别1规范()或(新性别2规范())
在where子句中,我做错了什么,或者应该如何将几个条件组合在一起?尝试以这种方式更改语句
Specification<Student> spec = (new GradeSpec().and(new AgeNotNullSpec()))
.or(new Gender1Spec().or(new Gender2Spec()));
Specification spec=(新的GradeSpec()和(新的agentnullspec())
.或(新性别1规范())或(新性别2规范());