Jquery 使用jqTransform从select获取id（表单中有多个select）

我有一个有3个选择的表单，并对其应用了jqTransform

<div class="selects">
<form id="form" class="form_comer" method="post" action="ajax/selects.php">
     <select id="select-local" name="select-local" class="select-index">
    <option selected="selected" value="">'.$select_comer_tipo.'</option>
    <option value="1">'.$select_comer_rest.'</option>
    <option value="2">'.$select_comer_bar.'</option>
    <option value="3">'.$select_comer_cafe.'</option>
     </select>
         <select id="select-ambiente" name="select-ambiente" class="select-index">
    <option value="">'.$select_comer_ambiente.'</option>
    <option value="1">'.$select_comer_animado.'</option>
    <option value="2">'.$select_comer_silencioso.'</option>
    <option value="3">'.$select_comer_glamouroso.'</option>
    </select>
        <select id="select-precio" name="select-precio" class="select-index">
    <option value="">'.$select_comer_precio.'</option>
    <option value="1">'.$select_comer_p1.'</option>
    <option value="2">'.$select_comer_p2.'</option>
    <option value="3">'.$select_comer_p3.'</option> 
    </select>                       
</form>
</div>

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它可能不太优雅，但这正是我所需要的：

var sel= ($(this).closest('div')).children('select').attr('id');

了解如何添加缺少的必要更改事件

var sel= ($(this).closest('div')).children('select').attr('id');