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使用jQUERY$.each()迭代返回的JSON对象_Jquery_Json_Iteration - Fatal编程技术网

使用jQUERY$.each()迭代返回的JSON对象

使用jQUERY$.each()迭代返回的JSON对象,jquery,json,iteration,Jquery,Json,Iteration,我使用jQuery的$.ajax方法调用getjson.php,它使用PHPs JSON_encode($data)返回一个JSON对象。我的JSON的结构如下所示 [ { “StoreKey”:“84”, “店名”:“区域1”, "0": "4,055.37", "1": "2,668.29", "2": "4,454.81", "3": "4,789.99", “4”:“无”, “5”:“无”, “6”:“无”, "7": "15,968.46" }, { “StoreKey”:“26”,

我使用jQuery的$.ajax方法调用getjson.php,它使用PHPs JSON_encode($data)返回一个JSON对象。我的JSON的结构如下所示

[ { “StoreKey”:“84”, “店名”:“区域1”, "0": "4,055.37", "1": "2,668.29", "2": "4,454.81", "3": "4,789.99", “4”:“无”, “5”:“无”, “6”:“无”, "7": "15,968.46" }, { “StoreKey”:“26”, “店名”:“区域2”, "0": "2,368.09", "1": "2,270.24", "2": "1,806.76", "3": "1,656.15", “4”:“无”, “5”:“无”, “6”:“无”, "7": "8,101.24" }, { “StoreKey”:“每日”, “店名”:“总计”, "0": "92,614.45", "1": "98,126.78", "2": "104,157.04", "3": "102,581.87", “4”:“无”, “5”:“无”, “6”:“无”, "7": 397480.14 }]

我可以使用$('#responseDiv').html(result);})显示JSON对象; 但是我想使用$.each()方法分析每一行

使用$.each()遍历JSON对象时,只显示最后一个JSON对象。这将显示最后一个JSON对象->“7”:397480.14

var data = $.parseJSON(result);
  $.each(data,function(row,store)  {    
   $.each(store,function(key,value) {
     $('#responseDiv').html(value); 
     });        
  })
我们的目标是将JSON对象包装为每行的标记和每列的标记,以获得表/网格外观。**

AJAX请求函数

$.ajax  //jQuery Syntax-ajax.api!
  ({
     type: "POST",
     url: "includes/getjson.php", //----my php scripts/codes
     data: "date="+x, 
     datatype: "json",
     success: function(result)
     {
      var data = $.parseJSON(result);
      $.each(data,function(row,store)  {    
        $.each(store,function(key,value) {
            $('#responseDiv').html(value);  });     
           }) 
     }
   }); 
}

这是我没有做或做得不正确的事情…

您每次都在替换#responseDiv的内容-您想附加它吗

$('#responseDiv').html($('#responseDiv').html() + value);
或简称:

$('#responseDiv').append(value);

您每次都要替换#responseDiv的内容-您想附加它吗

$('#responseDiv').html($('#responseDiv').html() + value);
或简称:

$('#responseDiv').append(value);

如果您试图创建一个不基于json对象的行的表,我建议使用像or这样的模板引擎。然后,您只需创建一个模板,并将返回对象发送给它进行渲染

<!-- Template content --> 
<textarea id="myTemplate" style="display:none"> 

        {#foreach $T as record}
        <tr>
           <td>{$T.record.StoreKey}</td>
           <td>{$T.record.StoreName}</td>
                       <td>{$T.record.0}</td>
        </tr>
        {#/for}
</textarea> 

如果您试图创建一个不基于json对象的行的表,我建议使用像or这样的模板引擎。然后,您只需创建一个模板,并将返回对象发送给它进行渲染

<!-- Template content --> 
<textarea id="myTemplate" style="display:none"> 

        {#foreach $T as record}
        <tr>
           <td>{$T.record.StoreKey}</td>
           <td>{$T.record.StoreName}</td>
                       <td>{$T.record.0}</td>
        </tr>
        {#/for}
</textarea>