如何循环Jquery变量选项列表

以下是原始函数*-------------------------------------

function lang(t) {

        $(".OutLbl").each(function () {
             $(this).html(
               $(this).html()
                .replace("Search", diction.wordlist.Search[t])
                .replace("By", diction.wordlist.By[t])
                .replace("Select Language", diction.wordlist["Select Language"][t])
                .replace("ID", diction.wordlist["ID"][t])
              );
            });
    };

var diction = {
    wordlist: {
        "Search": {
            dh: "ހޯދާ",
            en: "Search"
        },
        "By": {
            dh: "އިން",
            en: "by"
        },
        "Select Language": {
            dh: "ބަސް ޙިޔާރުކުރޭ",
            en: "Select Language"
        },
        "ID": {
            dh: "އައިޑީ",
            en: "ID"
        },
    }
}

**我需要简化上述函数中的替换，而不是通过

为diction[wordlist]选项中的每个选项循环

有点像**

function lang(t) {
       $(diction[wordlist] options).each( function () {
       var lll = this;
              $(".OutLbl").each(function () {
                $(this).html(
                $(this).html().replace(lll, diction.wordlist[lll][t])
                );
            });
        });
    };

---

问题是如何在一个函数中循环变量的所有选项（在我的例子中是diction.wordlist），因为我上面尝试的那个选项不起作用

提前谢谢

我建议：

var diction = {
    wordlist: {
        "Search": {
            dh: "ހޯދާ",
            en: "Search"
        },
        "By": {
            dh: "އިން",
            en: "by"
        },
        "Select Language": {
            dh: "ބަސް ޙިޔާރުކުރޭ",
            en: "Select Language"
        },
        "ID": {
            dh: "އައިޑީ",
            en: "ID"
        }
    }
};

function lang(t) {
    // initialise an array to store all the words/phrases:
    var words = [];
    // iterate over the properties of the 'diction.wordlist' object:
    for (var word in diction.wordlist) {
        // if the property is a property of the defined object:
        if (diction.wordlist.hasOwnProperty(word)) {
            // we push that word into the array:
            words.push(word);
        }
    }

    // creating a new RegExp, using the constructor, which allows us
    // to use variables. We create the literal regular expression:
    // /(Search)|(By)|(Select Language)|(ID)/
    // and use case-insensitivity (i) and global (g) flags:
    var reg = new RegExp('(' + words.join(')|(') + ')', 'gi');

    // using the html method and its anonymous function, which exposes:
    // i: the index of the current element amongst the collection, and
    // oldhtml: the current innerHTML of the current element (prior to manipulation)
    $('.OutLbl ').html(function (index, oldhtml) {
        // we return the html after replacing the matchedWords (using the callback
        // of replace():
        return oldhtml.replace(reg, function (matchedWord) {
            // finding the, for example, 'diction.wordlist['Search'][t]:
            return diction.wordlist[matchedWord][t];
        });
    });
}

$('#trigger').on('click', function(e){
    e.preventDefault();
    lang('dh');
});

参考资料：

• JavaScript:

---

在循环中为…尝试一个

，使用
hasOwnProperty
进行消毒，以避免通过原型继承属性：

$(".OutLbl").each(function () {
  var html = $(this).html();
  for(var word in diction.wordlist){
    if(diction.wordlist.hasOwnProperty(word))  {
      html = html.replace(word, diction.wordlist[word][t])
    }
  }
  $(this).html(html);
});

请注意，与当前代码一样，它将仅替换每个单词的第一次出现

要替换所有表达式，请使用带有
g
标志的正则表达式，并进行转义

你能澄清你的问题吗？问题是什么？问题是如何在一个函数中循环变量的所有选项（在我的例子中是diction.wordlist），因为我在上面尝试的一个不起作用。相关/可能的dup：谢谢+1这很完美。很高兴能提供帮助。
var regExp = new RegExp(word.replace(/[.^$*+?()[{\|]/g, '\\$&'), "g");
html = html.replace(regExp, diction.wordlist[word][t])