Jquery Google地图错误未捕获语法错误：意外标记）

我正在使用buddy press，并在个人资料中添加了一个谷歌地图。有时地图显示正确，有时则不正确

我检查了页面上地图没有显示的inspect元素，得到了一个未捕获的语法错误：意外的标记有人能帮我解决缺少地图的问题吗

以下是供参考的php代码：

<script type="text/javascript">
jQuery.noConflict();

jQuery(document).ready(function() { 
if (jQuery('#member-map').length != 0) {

    function a_page_maps() {

        geocoder = new google.maps.Geocoder();
        var latlng = new google.maps.LatLng(26.745610382199022, 2.63671875);
        var myOptions = {
            zoom: 2,
            center: latlng,
            mapTypeId: google.maps.MapTypeId.ROADMAP
        };
        var map = new google.maps.Map(document.getElementById("member-map"), myOptions);

        var gmarkers = [];

        function createMarker(latlng,html,url,icon) {

            var contentString = html;
            var marker = new google.maps.Marker({
                position: latlng,
                map: map,
                icon: icon
            });

            gmarkers.push(marker);

            var infowindow = new google.maps.InfoWindow;

            google.maps.event.addListener(marker, 'mouseover', function() {
                infowindow.setContent(contentString); 
                infowindow.open(map,marker);
            });

            google.maps.event.addListener(marker, 'mouseout', function() {
                infowindow.close(map,marker);
            });

            google.maps.event.addListener(marker, 'click', function() {
                window.location = url;
            });

        }
        <?php
        foreach ($placel as $place) {
        if(get_post_meta($place, 'article_location', true) <> "") {
        ?>
var image = '<?php echo get_bloginfo('template_url'); ?>/images/red-pushpin.png';
                var point = new google.maps.LatLng(<?php echo get_post_meta($place, 'article_location_latlon', true); ?>);
            var html = "<h5><?php echo get_post_meta($place, 'article_location', true); ?></h5><p class='popup'><em>&darr; Click to see articles about this location &darr;</em></p>";
            var url = '<?php echo get_bloginfo('wpurl'); ?>/locations/?location=<?php echo urlencode(get_post_meta($place, 'article_location', true)); ?>';

            var marker = createMarker(point,html,url,image);

        <?php
        }
        }
        ?>

        <?php
        foreach ($placegol as $placego) {
        if(get_post_meta($placego, 'article_location', true) <> "") {
        ?>

            var image = '<?php echo get_bloginfo('template_url'); ?>/images/grn-pushpin.png';
            var point = new google.maps.LatLng(<?php echo get_post_meta($placego, 'article_location_latlon', true); ?>);
            var html = "<h5><?php echo get_post_meta($placego, 'article_location', true); ?></h5><p class='popup'><em>&darr; Click to see articles about this location &darr;</em></p>";
            var url = '<?php echo get_bloginfo('wpurl'); ?>/locations/?location=<?php echo urlencode(get_post_meta($placego, 'article_location', true)); ?>';

            var marker = createMarker(point,html,url,image);
        <?php
        }
        }
        ?>
    }
        a_page_maps();   
    }    
});
</script>

应该是

 var infowindow = new google.maps.InfoWindow();

---

嵌套函数是个坏主意。lnrbob所说的是，发布实际生成的javascript，而不是PHP代码。

您收到的错误消息意味着您的代码中缺少一条。使用诸如Firebug for FF或内置开发工具Chrome&Safari之类的调试工具，它们将为您指出缺少角色的确切位置！通常，在每个语法错误旁边都会有一个行号，您可以单击该行号查看并及时修复错误。请看，将生成的javascript代码添加到问题中也是有意义的——这应该比php更容易发现javascript错误。

 var infowindow = new google.maps.InfoWindow();