Spring MVC-仅从外部json获取单个对象

我需要使用RESTApi，它会给我一个JSON输出，如下所示

{
"id": "e5d5ccc0-8da4-430d-b0ec-096d17ae2af8",
"car": [
{
    "identifier": "XX000YY",
    "formattedAddress": "Address 1",
    "lat": 45.841664,
    "lng": 18.199905,
    "isOn": false,
    "odometer": 763.4,

}
],
"location": "92589f4a-8c6e-4494-8548-b5428f8fa598"
}

RestTemplate restTemplate = new RestTemplate();
ResponseEntity<Wrapper> response = restTemplate.exchange(url, HttpMethod.POST, httpEntity,wrapper);

通常我会创建一个包装器对象

public class Wrapper{

private String id;

private Car car;

private String location;

//getters and setters

}

然后在我的控制器中，我会这样做

{
"id": "e5d5ccc0-8da4-430d-b0ec-096d17ae2af8",
"car": [
{
    "identifier": "XX000YY",
    "formattedAddress": "Address 1",
    "lat": 45.841664,
    "lng": 18.199905,
    "isOn": false,
    "odometer": 763.4,

}
],
"location": "92589f4a-8c6e-4494-8548-b5428f8fa598"
}

RestTemplate restTemplate = new RestTemplate();
ResponseEntity<Wrapper> response = restTemplate.exchange(url, HttpMethod.POST, httpEntity,wrapper);

RestTemplate RestTemplate=new RestTemplate（）；
ResponseEntity response=restemplate.exchange（url、HttpMethod.POST、httpEntity、包装器）；

得到回应

---

但基本上我只需要

Car

对象，所以我想如果有办法只返回it而不是整个包装器，并从中获取

Car

对象，那么首先，您必须创建一个可序列化的对象，如下所示：

Car.java

package com.wrapper;


public class Car implements Serializable{

public String identifier;
public String formattedAddress;
public Float lat;
public Float lng;
public Boolean isOn;
public Float odometer;

}

package com.wrapper;

import java.util.List;

public class Wrapper implements Serializable{

public String id;
public List<Car> car = null;
public String location;

}

Wrapper.java

package com.wrapper;


public class Car implements Serializable{

public String identifier;
public String formattedAddress;
public Float lat;
public Float lng;
public Boolean isOn;
public Float odometer;

}

package com.wrapper;

import java.util.List;

public class Wrapper implements Serializable{

public String id;
public List<Car> car = null;
public String location;

}