Linq 如何聚合联接?
我有三个相关的表格:Linq 如何聚合联接?,linq,linq-to-objects,aggregate,Linq,Linq To Objects,Aggregate,我有三个相关的表格: Employee(EmployeeId, EmployeeName) Skill(SkillId, SkillName) EmployeeSkill(EmployeSkillId, EmployeeId, SkillId) employeeskillid是一个标识 数据库中的行如下所示: John Doe, "Skill-1, Skill2, Skill-3" 员工表: 也就是说,将该员工的技能名称连接到单个字符串中 我尝试了以下方法,但不起作用
Employee(EmployeeId, EmployeeName)
Skill(SkillId, SkillName)
EmployeeSkill(EmployeSkillId, EmployeeId, SkillId)
employeeskillid
是一个标识
数据库中的行如下所示:
John Doe, "Skill-1, Skill2, Skill-3"
员工表:
也就是说,将该员工的技能名称连接到单个字符串中
我尝试了以下方法,但不起作用
var query = from emp in Employee.All()
from es in emp.EmployeeSkills
join sk in Skill.All() on es.SkillId equals sk.SkillId
group sk by new {emp.EmployeeName} into g
select new TestEntity
{
Name = g.Key.EmployeeName,
Skills = g.Aggregate(new StringBuilder(),
(sb, grp_row) => sb.Append(grp_row.SkillName))
.ToString()
};
技能名称的聚合列表返回为空。我如何才能做到这一点?听起来您可以将加入作为选择的一部分:
var query = from emp in Employee.All()
select new TestEntity {
Name = emp.EmployeeName,
Skills = string.Join(", ",
(from es in emp.EmployeeSkills
join sk in Skill.All() on es.SkillId equals sk.SkillId
select sk.SkillName)) };
现在,我们将分别为每一个单独地进行连接,这不是非常有效。另一个选项是首先构建从技能ID到技能名称的映射:
var skillMap = Skill.All().ToDictionary(sk => sk.SkillId,
sk => sk.SkillName);
那么主查询就很简单了:
var query = from emp in Employee.All()
select new TestEntity {
Name = emp.EmployeeName,
Skills = string.Join(", ",
emp.EmployeeSkills.Select(sk => skillMap[sk.SkillId]))};
最终有很多方法可以剥这只猫的皮-例如,如果你想坚持你原来的方法,那仍然是可行的。我会这样做:
var query = from emp in Employee.All()
from es in emp.EmployeeSkills
join sk in Skill.All() on es.SkillId equals sk.SkillId
group sk.SkillName by emp into g
select new TestEntity
{
Name = g.Key.EmployeeName,
Skills = string.Join(", ", g)
};
在这一点上,它与原始查询非常相似,只是使用了string.Join
而不是Aggregate
。如果这三种方法的技能列表都是空的,那么我怀疑你的数据有问题。我不清楚为什么您的第一个查询会“成功”,但技能列表是空的
编辑:好的,这里有一个简短但完整的示例:
using System;
using System.Collections.Generic;
using System.Linq;
public class Employee
{
public int EmployeeId { get; set; }
public string EmployeeName { get; set; }
public static List<Employee> All { get; set; }
public IEnumerable<EmployeeSkill> EmployeeSkills
{
get
{
return EmployeeSkill.All
.Where(x => x.EmployeeId == EmployeeId);
}
}
}
public class Skill
{
public string SkillName { get; set; }
public int SkillId { get; set; }
public static List<Skill> All { get; set; }
}
public class EmployeeSkill
{
public int SkillId { get; set; }
public int EmployeeId { get; set; }
public static List<EmployeeSkill> All { get; set; }
}
class Test
{
static void Main()
{
Skill.All = new List<Skill>
{
new Skill { SkillName = "C#", SkillId = 1},
new Skill { SkillName = "Java", SkillId = 2},
new Skill { SkillName = "C++", SkillId = 3},
};
Employee.All = new List<Employee>
{
new Employee { EmployeeName = "Fred", EmployeeId = 1 },
new Employee { EmployeeName = "Ginger", EmployeeId = 2 },
};
EmployeeSkill.All = new List<EmployeeSkill>
{
new EmployeeSkill { SkillId = 1, EmployeeId = 1 },
new EmployeeSkill { SkillId = 2, EmployeeId = 1 },
new EmployeeSkill { SkillId = 2, EmployeeId = 2 },
new EmployeeSkill { SkillId = 3, EmployeeId = 2 },
};
var query = from emp in Employee.All
from es in emp.EmployeeSkills
join sk in Skill.All on es.SkillId equals sk.SkillId
group sk.SkillName by emp.EmployeeName into g
select new
{
Name = g.Key,
Skills = string.Join(", ", g)
};
foreach (var result in query)
{
Console.WriteLine(result);
}
}
}
嗨,乔恩。谢谢你这么快回复。这很奇怪,但两个选项都将Skills属性返回为空。我确信这不是数据,因为只使用连接并为每个员工/技能返回一行就行了。知道是什么导致聚合不起作用吗?@silverCORE:听起来很奇怪。。。如果您添加更改以使用“Skills=g.Count().ToString();”之类的内容,您是否获得了正确数量的技能?如果所有的方法都给出了相同的奇怪结果,那听起来确实有数据问题。如果你能给出一个简短但完整的例子,那将非常有帮助。我会尝试自己建立一个。让我粘贴Jon的数据,并尝试g.计数。在上一个示例中,显示“emp.EmployeeName下的group sk.SkillName”的部分显然使尝试使用g.Key.EmployeeName变得不可行。至少我的智能感知没有接收到它。@silverCORE:是的,应该是按emp分组,或者按emp.EmployeeName分组,然后只使用g.Key。我已经编辑了这个查询,还包括了一个简短但完整的示例。我想知道你是否只是没能正确显示结果?我认为这个问题很好。乔恩,你就是那个人。谢谢你抽出时间来帮助我。非常感谢。我已经为你安排好了问题的格式。应该给你一个想法,如何得到你未来的问题你想要它。谢谢杰夫M,我一定会学会怎么做:)
var query = from emp in Employee.All()
select new TestEntity {
Name = emp.EmployeeName,
Skills = string.Join(", ",
emp.EmployeeSkills.Select(sk => skillMap[sk.SkillId]))};
var query = from emp in Employee.All()
from es in emp.EmployeeSkills
join sk in Skill.All() on es.SkillId equals sk.SkillId
group sk.SkillName by emp into g
select new TestEntity
{
Name = g.Key.EmployeeName,
Skills = string.Join(", ", g)
};
using System;
using System.Collections.Generic;
using System.Linq;
public class Employee
{
public int EmployeeId { get; set; }
public string EmployeeName { get; set; }
public static List<Employee> All { get; set; }
public IEnumerable<EmployeeSkill> EmployeeSkills
{
get
{
return EmployeeSkill.All
.Where(x => x.EmployeeId == EmployeeId);
}
}
}
public class Skill
{
public string SkillName { get; set; }
public int SkillId { get; set; }
public static List<Skill> All { get; set; }
}
public class EmployeeSkill
{
public int SkillId { get; set; }
public int EmployeeId { get; set; }
public static List<EmployeeSkill> All { get; set; }
}
class Test
{
static void Main()
{
Skill.All = new List<Skill>
{
new Skill { SkillName = "C#", SkillId = 1},
new Skill { SkillName = "Java", SkillId = 2},
new Skill { SkillName = "C++", SkillId = 3},
};
Employee.All = new List<Employee>
{
new Employee { EmployeeName = "Fred", EmployeeId = 1 },
new Employee { EmployeeName = "Ginger", EmployeeId = 2 },
};
EmployeeSkill.All = new List<EmployeeSkill>
{
new EmployeeSkill { SkillId = 1, EmployeeId = 1 },
new EmployeeSkill { SkillId = 2, EmployeeId = 1 },
new EmployeeSkill { SkillId = 2, EmployeeId = 2 },
new EmployeeSkill { SkillId = 3, EmployeeId = 2 },
};
var query = from emp in Employee.All
from es in emp.EmployeeSkills
join sk in Skill.All on es.SkillId equals sk.SkillId
group sk.SkillName by emp.EmployeeName into g
select new
{
Name = g.Key,
Skills = string.Join(", ", g)
};
foreach (var result in query)
{
Console.WriteLine(result);
}
}
}
{ Name = Fred, Skills = C#, Java }
{ Name = Ginger, Skills = Java, C++ }