List 使用csv.reader生成while循环打印多个列表

我有一个excel文档，里面填充了我希望python代码打印出来的信息。为了让大家了解我的excel文档的外观，我将打印一些代码：

import csv
file = csv.reader(open("n:\population.csv"))
print file.next()

这为我们提供了以下输出：

   ['country', 'country isocode', 'year', 'POP']

但这不是我要打印的部分，相关信息在其他行中，因此如果我再输入一个打印文件，我们将获得以下信息：

['Netherlands', 'NLD', '1950', '10113.527']

如果这是我需要的相关信息，现在我只需要打印出年份和人口流行，并对我文档中的每一行执行此操作。因此，我提出了以下代码来实现这一点：

import csv
file = csv.reader(open("population.csv"))
print file.next()


def print_population_list(filename):
    population_list_length = len("population.csv")
    number = 0
    line = file.next()
    while number < population_list_length:
        print line[2:]
        population_list_length = population_list_length - 1



print_population_list('N:\population.csv')

那么，如何让代码打印出文档的下一行，而不是一次又一次地打印同一行，直到数字>填充列表长度

---

如果有人能帮我解决这个问题，我会非常感激的。你没有做的事情之一就是在while循环或for循环中前进

您已将行定义为file.next，但随后告诉它从同一行反复打印零件

试着这样做，在打印数据后，记下在每个循环结束时推进行：

def print_population_list(filename):
    population_list_length = len("population.csv")
    number = 0
    line = file.next()
    while number < population_list_length:
        print line[2:]
        # the next line of code advances the line in the file
        line = file.next()
        population_list_length = population_list_length - 1

    # you don't need to advance the line here, 
    # as you've already advanced it at the end of the last loop

    for contry, isocode, year, population in 
        print line[2:]
        # the next line of code advances the line in the file
        line = file.next()
        population_list_length = population_list_length - 1

def print_population_list(filename):
    population_list_length = len("population.csv")
    number = 0
    line = file.next()
    while number < population_list_length:
        print line[2:]
        # the next line of code advances the line in the file
        line = file.next()
        population_list_length = population_list_length - 1

    # you don't need to advance the line here, 
    # as you've already advanced it at the end of the last loop

    for contry, isocode, year, population in 
        print line[2:]
        # the next line of code advances the line in the file
        line = file.next()
        population_list_length = population_list_length - 1