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Mongodb Mongo聚合到PostgresSQL_Mongodb_Postgresql_Aggregation Framework_Node Postgres - Fatal编程技术网
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Mongodb Mongo聚合到PostgresSQL

mongodb postgresql

Mongodb Mongo聚合到PostgresSQL,mongodb,postgresql,aggregation-framework,node-postgres,Mongodb,Postgresql,Aggregation Framework,Node Postgres,我正在尝试将Mongo聚合转换为PostgresSQL等效项，并将其传递给节点pgp执行- Mongo聚合： [{"$group":{"count":{"$sum":1},"_id":{"media":"$media","user":"$user"}}},{"$sort":{"count":-1}}] PostgresSQL格式： const qs = `SELECT ${columns.join()} FROM $1:name ${wherePattern} ${sortPattern} $

我正在尝试将Mongo聚合转换为PostgresSQL等效项，并将其传递给节点pgp执行-

Mongo聚合：

[{"$group":{"count":{"$sum":1},"_id":{"media":"$media","user":"$user"}}},{"$sort":{"count":-1}}]
PostgresSQL格式：

const qs = `SELECT ${columns.join()} FROM $1:name ${wherePattern} ${sortPattern} ${limitPattern} ${skipPattern} ${groupPattern}`;
结果pSQL查询

SELECT COUNT(*) AS "count", "media" AS "media", "user" AS "user", * FROM "Conversions"  ORDER BY   "count" DESC   GROUP BY ' "media", "user" '
来自节点postgres的错误：

错误：未捕获的内部服务器错误。在“组”处或附近出现语法错误

在上面形成的查询中会有什么错误？

order by
需要在
group by
之后进行操作，我会得到以下错误：列“Conversion.objectId”必须出现在group by子句中或用于聚合函数（简而言之：从
选择
列表中删除
*
）