MySQL两个查询的计数之和

我（非常）不熟悉MySQL。请原谅我的无知

我正在制作一个曲棍球统计数据库，我需要把所有助攻和所有进球加在一起，得到“总分”。我已经计算出了两个查询，但我无法计算出如何将这两个查询相加。 以下是查询：

select player_id, count(*) 
from(select * from 1st_assists
union
select * from 2nd_assists) as tem
join players on tem.fk_player_id=players.player_id
group by fk_player_id
order by count(*) desc

select player_id, count(*)
from goals_for
join shots_for on goals_for.fk_shot_for_id=shots_for.shot_for_id
join players on shots_for.fk_player_id=players.player_id
group by player_id
order by count(*) desc;

如何将这两个查询合并为一个查询并获得两个计数的总和

下面是每个查询的结果

Total Assists
player_id   count(*)
79      24
55      22
45      17
90      16
40      15
65      15
37      13
1       13
20      11
84      11
64      10
27      9
93      7
8       5
24      3
57      1

Goals
player_id   count(*)
90      38
37      28
40      19
55      13
45      11
1       8
24      8
20      8
84      8
27      6
8       5
79      4
65      4
93      1
64      1

---

这是未经测试的，但请您尝试一下：

select p.player_first_name, p.player_last_name, (count1+count2) as total_count
from
(select player_id, count(*) count1
from(select * from 1st_assists
union
select * from 2nd_assists) as tem
join players on tem.fk_player_id=players.player_id
group by fk_player_id
order by count(*) desc) q1
left join
(select player_id, count(*) count2
from goals_for
join shots_for on goals_for.fk_shot_for_id=shots_for.shot_for_id
join players on shots_for.fk_player_id=players.player_id
group by player_id) q2
ON q1.player_id=q2.player_id
left join player p ON q1.player_id=p.player_id
order by (count1+count2) desc;

---

你想得到每个玩家的总数吗？是的，没错。每个玩家的总数。是否所有玩家都出现在您的两个查询中？这看起来很有效！！如何按总分对desc进行排序？我尝试了几件事，但都没有成功……没关系，我犯了个愚蠢的语法错误。一切都好。如果我能知道你是怎么做到的。我可能要花点时间盯着它看……非常感谢，你只用了10分钟就回答了。我应该在12小时前问这个问题！！那么，查询是否一切正常？我只在player_id列中加入了这两个查询，然后添加了每个子查询提供的计数。请参阅编辑，了解按总计数降序排列的顺序。是。知道了。再次感谢！！