mysql查询2个带有count的表

我有两张桌子。一个叫做艺术家。以下是表格结构：

artistID lastname firstname nationality dateofbirth datedcease

另一个表称为

work

workId title copy medium description artist ID

什么是SQL查询以列出数据库中记录了多个副本的任何艺术作品（包括创作该作品的艺术家）的详细信息？

尝试以下操作：

SELECT 
  w.copy, w.title, w.description, w.medium, 
  a.firstname + ' ' + a.lastname AS 'Artist created the work'
FROM artists a
INNER JOIN
(
    SELECT * 
    FROM work 
    WHERE artistID IN
    ( 
        SELECT artistID
        FROM work 
        GROUP BY artistID
        HAVING COUNT(*) > 1 
    )
) w ON a.artistID = w.artistID

这里有一个

试试这个：

SELECT 
  w.copy, w.title, w.description, w.medium, 
  a.firstname + ' ' + a.lastname AS 'Artist created the work'
FROM artists a
INNER JOIN
(
    SELECT * 
    FROM work 
    WHERE artistID IN
    ( 
        SELECT artistID
        FROM work 
        GROUP BY artistID
        HAVING COUNT(*) > 1 
    )
) w ON a.artistID = w.artistID

这是一个