从两个表进行mysql join或concat查询以获得月份注册

我有两张表，分别是经销商注册和索赔数据

SELECT YEAR(claim_dt) AS `Year`, 
       MONTHNAME(claim_dt) AS `Month`, 
       COUNT(distinct `uniquecode`) AS `No of Reg` 
FROM claim_data
WHERE YEAR(claim_dt) = '2016' 
GROUP BY `Year`, `Month` 
ORDER BY MONTH(claim_dt) DESC


SELECT YEAR(reg_date) AS `Year`, 
       MONTHNAME(reg_date) AS `Month`, 
       COUNT(*) AS `No of Reg`
FROM reg_dealer 
WHERE YEAR(reg_date) = '2016' 
GROUP BY `Year`, `Month` 
ORDER BY MONTH(reg_date)  DESC

我从两个表中以相同的格式得到每月结果

Year----------Month----------No_of_Reg
2016          March           150
2016          February        125
2016          Janurary         75

我要一次完成注册和索赔

Year----------Month----------No_of_Reg---------No_of_claims
2016          March           150                350
2016          February        125                250
2016          Janurary         75                150

也希望得到唯一的索赔人

请帮助加入查询

SELECT t1.Year, t1.Month, `No of Reg`, `No of Claims`
FROM (SELECT YEAR(claim_dt) AS `Year`, MONTHNAME(claim_dt) AS `Month`, MONTH(claim_dt) AS MonthNum, COUNT(distinct `uniquecode`) AS `No of Claims` 
        FROM claim_data 
        WHERE YEAR(claim_dt) = '2016' GROUP BY `Year`, `Month`) AS t1
JOIN (SELECT YEAR(reg_date) AS `Year`, MONTH(claim_dt) AS MonthNum, COUNT(*) AS `No of Reg` 
        FROM reg_dealer 
        WHERE YEAR(reg_date) = '2016' 
        GROUP BY `Year`, `MonthNum`) AS t2
    ON t1.Year = t2.Year AND t1.MonthNum = t2.MonthNum
ORDER BY t1.Year, t1.MonthNum DESC

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加入年份和月份的两个查询。感谢您的回答，但查询未执行，在“on子句”中获取错误未知列“t2.month”，我将t2.month替换为t2.MonthNum，但没有结果。我的意思是将其更改为

MonthNum

。但是，sir query收到消息，您的SQL查询已成功执行（查询耗时0.0126秒）但是没有结果这里只会有几个月的结果，既有索赔也有注册。现在就可以了！脚本正在工作，但没有任何声明输出与我编写的查询不完全相同