Mysql 选择sql表的最后3行

我想选择sql表的最后3行。我知道我应该使用SELECT*FROM table ORDER BY DESC LIMIT 3，但这段代码的问题是它从末尾选择行。例如，它选择30，然后选择29，然后选择28。但是，我需要这种格式：28，29，30。有什么建议吗？

比如：

select * from (select * from table order by x desc limit 3) order by x;

---

试着这样做：-

  SELECT * FROM reset 
  WHERE username = '$table' ORDER BY id  ASC LIMIT (FOUND_ROWS() - 3), 3

试试这个：

SELECT * FROM (
  SELECT * FROM reset ORDER BY id DESC LIMIT 3
) as r ORDER BY id

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我希望这有助于解决你的问题

select * from
(
select *  from reset 
order by id DESC LIMIT 3
 ) t
order by id ASC 

试一试

试试这个手动的

简单又简单

Select * From tableName where 
PKCol=(select count(*) from tableName ) 
OR 
PKCol=(select count(*) from tableName )-1 
OR 
PKCol=(select count(*) from tableName )-2 
order by PKCol desc;

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我尝试了这段代码，但出现了错误：mysql_querySELECT*FROM SELECT nobuzz FROM reset其中username='$table'ORDER BY id DESC LIMIT$resetnum2 ORDER BY id；请仅尝试以下操作：-从ASC限制找到的重置顺序中选择*行-3、3，并检查它是否以升序给出表中的最后3行！！！我尝试了这段代码，但出现了错误：mysql_querySELECT*FROM SELECT nobuzz FROM reset其中username='$table'ORDER BY id DESC LIMIT$resetnum2 ORDER BY id；

Select * From tableName where 
PKCol=(select count(*) from tableName ) 
OR 
PKCol=(select count(*) from tableName )-1 
OR 
PKCol=(select count(*) from tableName )-2 
order by PKCol desc;