MySql-Update/Case

我有一张桌子

TestNumber (int primary key)
InactiveBitwise (int)

我发出以下命令：

UPDATE tests SET CASE
        WHEN TestNumber = 2 THEN InactiveBitwise = (InactiveBitwise | 4)
        WHEN TestNumber = 3 THEN InactiveBitwise = (InactiveBitwise | 8)
END WHERE TestNumber IN (2, 3)

但它给出了错误的答案

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CASE WHEN TestNumber = 2 THEN InactiveBitwise = (InactiveBitwise |'

TestNumber=2和3都存在，因为我以前是通过调用数据库得到它们的

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有人知道它不喜欢什么吗？

您需要指定要更改的列的值，案例将仅确定返回值：

UPDATE tests SET InactiveBitwise = CASE
        WHEN TestNumber = 2 THEN (InactiveBitwise | 4)
        WHEN TestNumber = 3 THEN (InactiveBitwise | 8)
     END
WHERE TestNumber IN (2, 3)