Mysql 从select语句向表中插入值

我有以下SQL查询：

INSERT INTO site_city_address (`cityName`, `cityCode`, `stateId`) VALUES  (SELECT a.city, a.cityCode,  b.stateId
  FROM site_address_dropdown a INNER JOIN site_state_address b
    ON a.state = b.stateName);

我知道这可能是错的。我要做的是将a.city、a.cityCode和b.stateId的值作为cityName、cityCode和stateId插入shopious\u city\u地址。

---

如何操作？

删除

值

关键字<代码>插入到…选择具有以下语法

INSERT INTO site_city_address (cityName, cityCode, stateId) 
SELECT  a.city, a.cityCode, b.stateId
FROM    site_address_dropdown a 
        INNER JOIN site_state_address b
            ON a.state = b.stateName

---

删除

值

关键字<代码>插入到…选择具有以下语法

INSERT INTO site_city_address (cityName, cityCode, stateId) 
SELECT  a.city, a.cityCode, b.stateId
FROM    site_address_dropdown a 
        INNER JOIN site_state_address b
            ON a.state = b.stateName

---

您可以在插入

后指定
值
或
选择
。在您的情况下，省略
值
：

INSERT  INTO site_city_address
        (`cityName`, `cityCode`, `stateId`) 
SELECT  a.city, a.cityCode, b.stateId
FROM    site_address_dropdown a 
INNER JOIN 
        site_state_address b
ON      a.state = b.stateName;

您可以在插入
后指定
值
或
选择
。在您的情况下，省略
值
：

INSERT  INTO site_city_address
        (`cityName`, `cityCode`, `stateId`) 
SELECT  a.city, a.cityCode, b.stateId
FROM    site_address_dropdown a 
INNER JOIN 
        site_state_address b
ON      a.state = b.stateName;