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Mysql 使用内部联接更新sql数据_Mysql_Sql_Database_Wordpress_Syntax - Fatal编程技术网

Mysql 使用内部联接更新sql数据

Mysql 使用内部联接更新sql数据,mysql,sql,database,wordpress,syntax,Mysql,Sql,Database,Wordpress,Syntax,我想将wordpress数据库中的帖子状态从草稿更改为垃圾,以便重复具有相同帖子标题的帖子,我使用此sql查询 UPDATE a.post_status SET `post_status` = 'trash' FROM wp_posts AS a INNER JOIN ( SELECT post_title, MIN( id ) AS min_id FROM wp_posts WHER

我想将wordpress数据库中的帖子状态从草稿更改为垃圾,以便重复具有相同帖子标题的帖子,我使用此sql查询

      UPDATE a.post_status SET `post_status` = 'trash'
        FROM wp_posts AS a
         INNER JOIN (
           SELECT post_title, MIN( id ) AS min_id
           FROM wp_posts
           WHERE post_type = 'post'
           AND post_status = 'draft'
           GROUP BY post_title
           HAVING COUNT( * ) > 1
         ) AS b ON b.post_title = a.post_title
        AND b.min_id <> a.id
        AND a.post_type = 'post'
        AND a.post_status = 'draft'

此查询的正确语法是什么?

MySQL中的正确语法不使用FROM:


请注意,我还将表格别名从无意义的字母改为更有意义的缩写。

感谢Gordon在这个语法中给出的答案。我发现其他错误是错误代码:1146表格“a.post_status”没有exist@hassanii现在试试。@草莓。非常感谢。
  Error Code: 1064
    Erreur de syntaxe près de 'FROM wp_posts AS a
     INNER JOIN (
       SELECT post_title, MIN( id ) AS min_id
      ' à la ligne 2
UPDATE post_status ps INNER JOIN
       (SELECT post_title, MIN( id ) AS min_id
        FROM wp_posts
        WHERE post_type = 'post' AND
              post_status = 'draft'
        GROUP BY post_title
        HAVING COUNT( * ) > 1
       ) p
       ON p.post_title = ps.post_title AND
          p.min_id <> ps.id AND
          ps.post_type = 'post' AND
          ps.post_status = 'draft'
 SET ps.post_status = 'trash';