在MySql中查找两个日期之间的秒差

我想知道从表字段

upload\u date

到现在执行查询的时间（以秒为单位）已经过去了多少时间。在阅读了MySQL的一些函数之后，我尝试了一下，但没那么幸运

如果值小于24小时，是否有方法以小时为单位返回值；如果值小于等于100天，是否有方法以天为单位返回值？否则，我将不得不用PHP编写代码

日期是当前的时间戳格式，只是为了澄清这一点

我试过这个：

SELECT DATE_SUB(NOW(), upload_date) FROM is_meeting_files

我也试过了，但相差0秒：

SELECT DATEDIFF(CURDATE(), upload_date) AS intval FROM is_meeting_files LIMIT 0,5;

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您可以相互减去unix时间戳值：

SELECT unix_timestamp(NOW()) - unix_timestamp(upload_date) from is_meeting_files;

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您可以相互减去unix时间戳值：

SELECT unix_timestamp(NOW()) - unix_timestamp(upload_date) from is_meeting_files;

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您可以这样做：

SELECT
    IF (TIMESTAMPDIFF(HOUR, upload_date, NOW()) <= 24,
        CONCAT(TIMESTAMPDIFF(HOUR, upload_date, NOW()), ' hours'),
        IF (TIMESTAMPDIFF(DAY, upload_date, NOW()) <= 100,
            CONCAT(TIMESTAMPDIFF(DAY, upload_date, NOW()), ' days'),
            CONCAT(TIMESTAMPDIFF(MONTH, upload_date, NOW()), ' months'),
        )
    ) as diff
FROM is_meeting_files;

选择
如果（TIMESTAMPDIFF（HOUR，upload_date，NOW（））您可以这样做：

SELECT
    IF (TIMESTAMPDIFF(HOUR, upload_date, NOW()) <= 24,
        CONCAT(TIMESTAMPDIFF(HOUR, upload_date, NOW()), ' hours'),
        IF (TIMESTAMPDIFF(DAY, upload_date, NOW()) <= 100,
            CONCAT(TIMESTAMPDIFF(DAY, upload_date, NOW()), ' days'),
            CONCAT(TIMESTAMPDIFF(MONTH, upload_date, NOW()), ' months'),
        )
    ) as diff
FROM is_meeting_files;

选择
如果（TIMESTAMPDIFF（HOUR，upload_date，NOW（））我是通过php完成的，但感谢您的帖子。我将尝试在我的sql查询中完成它。我是通过php完成的，但感谢您的帖子。我将尝试在我的sql查询中完成它。