mysql和psql语法中的差异——寻找最近的地理坐标
我发现一个psql代码如下所示:mysql和psql语法中的差异——寻找最近的地理坐标,mysql,postgresql,geolocation,coordinates,psql,Mysql,Postgresql,Geolocation,Coordinates,Psql,我发现一个psql代码如下所示: select * from ( SELECT *,( 3959 * acos( cos( radians(6.414478) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(12.466646) ) + sin( radians(6.414478) ) * sin( radians( lat ) ) ) ) AS distance FROM station_location ) al where
select * from (
SELECT *,( 3959 * acos( cos( radians(6.414478) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(12.466646) ) + sin( radians(6.414478) ) * sin( radians( lat ) ) ) ) AS distance
FROM station_location
) al
where distance < 5
ORDER BY distance
LIMIT 20;
问题是我完全不明白。
在我使用mysql之前,语法完全不同:
SELECT latitude, longitude, SQRT(
POW(69.1 * (latitude - [startlat]), 2) +
POW(69.1 * ([startlng] - longitude) * COS(latitude / 57.3), 2)) AS distance
FROM TableName HAVING distance < 25 ORDER BY distance;
如何将此mysql指令转换为psql,以便用户的经度和纬度将越来越惊人?不评论计算本身,此PostgreSQL端口应该可以工作:
select * from (select SQRT(
POW(69.1 * (10 - 8), 2) +
POW(69.1 * (100 - 10) * COS(10 / 57.3), 2)) AS distance
from table) d where distance < 25 ORDER BY distance;