Node.js 查找与mongodb中提供的所有参数匹配的文档

假设我在collection bookDetails中有文档

doc1: {'bookData':{'bookName':'lotr','bookPart':'Part 3'}, 'library_name':'omega','libraryId':12166}

doc2: {'bookData':{'bookName':'hp','bookPart':'Part 7'}, 'library_name':'omega','libraryId':12199}

doc3: {'bookData':{'bookName':'hertu','bookPart':'Part 7'}, 'library_name':'omega','libraryId':9999}

我只想获取与所有字段库名：omega、库id:12199和bookName:hp匹配的文档

为此，我尝试：

wait collection.aggregate（[{$match:{library_name:'omega'}}，]）.exec（）；{$match:{libraryId:12199}

但我还想匹配书名：“hp”，这样我就可以得到所需的文档

如果有人需要更多信息，请告诉我。

演示-

---

演示-

加总

db.collection.aggregate([
  {
    $match: {
      library_name: "omega",
      libraryId: 12199,
      "bookData.bookName": "hp"
    }
  }
])

---

您可以将所有条件放在单个匹配阶段

{$match:{library_name:'omega'，libraryId:12199，bookName:'hp'}}

db.collection.aggregate([
  {
    $match: {
      library_name: "omega",
      libraryId: 12199,
      "bookData.bookName": "hp"
    }
  }
])