Node.js 归属关系-续集

我在使用sequelize+nodejs列出与belongTomany关联的记录时遇到问题

我有开发者和技术表。他们之间的关系是多对多的。要创建关系，请使用名为developers\u technologies的透视表

下面是代码的要点：模型（开发者、技术）、迁移（开发者、技术）和开发者的控制器

控制器开发人员索引的代码如下：

async index(req, res) {
const developers = await Developer.findAll({
  attributes: ['id', 'name', 'email'],
  include: [
    {
      model: Technologies,
      as: 'technologies',
      attributes: ['id', 'name'],
      through: { attributes: [] },
    },
  ],
});

return res.json(developers);}

返回：

[
    {
        "id": 25,
        "name": "Jon Doe",
        "email": "jondoe@gmail.com",
        "age": 27,
        "url_linkedin": "http://asdasdasd",
        "technologies": []
    }
]

我想知道为什么我没有收到与开发人员链接的技术，因为数据库中的developers\u technologies表已经填充，并且模型中的关系还可以

编辑： 根据请求生成的查询：

SELECT 
"Developer"."id", 
"Developer"."name", 
"Developer"."email", 
"technologies"."id" AS "technologies.id", 
"technologies"."name" AS "technologies.name", 
"technologies->developers_technologies"."created_at" AS "technologies.developers_technologies.createdAt", 
"technologies->developers_technologies"."updated_at" AS "technologies.developers_technologies.updatedAt", 
"technologies->developers_technologies"."developer_id" AS "technologies.developers_technologies.developer_id", 
"technologies->developers_technologies"."technology_id" AS "technologies.developers_technologies.technology_id" 
FROM "developers" AS "Developer" 
LEFT OUTER JOIN ( "developers_technologies" AS "technologies->developers_technologies" 
INNER JOIN "technologies" AS "technologies" ON "technologies"."id" = "technologies->developers_technologies"."developer_id") ON "Developer"."id" = "technologies->developers_technologies"."technology_id";

---

亲切问候，

尝试在

中的
项中指出属于许多
关联的
其他键。您还指示了错误的外键。对于开发者，它应该是
Developer\u id
，对于技术，它应该是
Technology\u id
：

模型开发人员

this.belongsToMany(models.Technology, {
      foreignKey: 'developer_id',
      otherKey: 'technology_id',
      through: 'developers_technologies',
      as: 'technologies',
    });

模型技术

this.belongsToMany(models.Developer, {
      foreignKey: 'technology_id',
      otherKey: 'developer_id',
      through: 'developers_technologies',
      as: 'developers',
    });

我补充道，相同的返回继续：/Very-square.。查看生成的SQL查询并将其添加到您的问题中