Pandas 从MongoDB字典到数据帧映射

Pandas 从MongoDB字典到数据帧映射,pandas,mongodb,dataframe,dictionary,Pandas,Mongodb,Dataframe,Dictionary,在我的示例中,我将DF转换为DICT列表以上传到MongoDB 现在我正在做相反的工作。从MongoDB查询中,我可以下载包含以下信息的DICT列表: [ {Info1: 3, City: BCN, Country: Spain}, {Info2: 5.6, City: BCN, Country: Spain}, {Info1: 4, City: Moscow, Country: Russia}, {Info2: 7, City: Moscow, Country: Russ

在我的示例中,我将DF转换为DICT列表以上传到MongoDB

现在我正在做相反的工作。从MongoDB查询中,我可以下载包含以下信息的DICT列表:

[
{Info1: 3,
 City: BCN,
 Country: Spain},

{Info2: 5.6,
 City: BCN,
 Country: Spain},

{Info1: 4,
 City: Moscow,
 Country: Russia},

{Info2: 7,
 City: Moscow,
 Country: Russia}
]
现在,我想创建一个表,如下所示:

City    Country   Info1  Info2
BCN      Spain    3      5.6   
Moscow   Russia   4      7   
  def generate_excel(ind_type):
     # first add columns
     columns = ["City", "Country"]

     # then  find all indictors filtered
     indicators = []
     for indicator in CUSTOMERS_COLLECTION.find().distinct("ID"):
         indicators.append(indicator)

     # then add the indicators in column
     columns = columns + indicators

     # First find all Ciudades
     cities = CUSTOMERS_COLLECTION.find()

      rows_list = []
     for ciudad in cities.distinct("City"):
        indicators = CUSTOMERS_COLLECTION.find({"City": ciudad})
        dict_ind = {}
        # then we create a dict of the indicators. It will be the row
        for indicator in indicators:
            dict_ind[indicator["ID"]] = indicator["Valor"]
            dict_ind["Country"] = indicator["Country"]
            dict_ind["City"] = indicator["City"]

     df_ = pd.DataFrame(rows_list, columns=columns)
     return df_
我现在的做法如下:

City    Country   Info1  Info2
BCN      Spain    3      5.6   
Moscow   Russia   4      7   
  def generate_excel(ind_type):
     # first add columns
     columns = ["City", "Country"]

     # then  find all indictors filtered
     indicators = []
     for indicator in CUSTOMERS_COLLECTION.find().distinct("ID"):
         indicators.append(indicator)

     # then add the indicators in column
     columns = columns + indicators

     # First find all Ciudades
     cities = CUSTOMERS_COLLECTION.find()

      rows_list = []
     for ciudad in cities.distinct("City"):
        indicators = CUSTOMERS_COLLECTION.find({"City": ciudad})
        dict_ind = {}
        # then we create a dict of the indicators. It will be the row
        for indicator in indicators:
            dict_ind[indicator["ID"]] = indicator["Valor"]
            dict_ind["Country"] = indicator["Country"]
            dict_ind["City"] = indicator["City"]

     df_ = pd.DataFrame(rows_list, columns=columns)
     return df_
正如我前面的问题一样,这是可行的,但似乎根本没有优化。MongoDB或DF中是否有允许正确映射字典的功能


谢谢

我不是100%的认为这对您有效,但在过去,我能够简单地将mongo查询转换为数据帧。例如:

q1=db.collection.find(#add whatever filters you need)
df= pd.DataFrame(q1)
请告诉我这是否有效